我正在尝试执行一个sql查询,其中包含一个使用DBAL的LIKE操作符。
基本上,我的查询如下:
public function getSubsiteByHostname($host){
$sql = "SELECT A.id, A.title, A.layout_id
FROM sites AS A
LEFT JOIN layouts B
ON A.layout_id = B.id
WHERE A.baseurl LIKE '%:host%'
";
$stmt = $this->db->prepare($sql);
$stmt->bindValue("host", $host);
$stmt->execute();
return $stmt->fetch();
}
SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '%'hostname.dev'%很明显,我对bindValue做了些错事
发布于 2014-03-10 12:10:25
答案比我想象的要容易,就像亚当建议的那样。
$stmt->bindValue("host", '%'.$host.'%');https://stackoverflow.com/questions/22299364
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