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Rails教程,Michael,第6章,验证用户
EN

Stack Overflow用户
提问于 2014-03-07 20:04:22
回答 1查看 788关注 0票数 1

我一辈子都搞不懂这三项考试为什么不及格。我对rails非常陌生,但我觉得好像我已经尝试过所有的东西,至少根据教程是这样的。我确信这是显而易见的事情,但我试图找到一个答案却是徒劳的。我的失败测试如下(摘自Michael的Rails教程)。谢谢。

失败:

1)当密码不存在时,用户返回具有有效密码失败/错误的身份验证方法的返回值:它{应该eq found_user.authenticate(@user.password) } NoMethodError:未定义方法authenticate' for nil:NilClass # ./spec/models/user_spec.rb:94:in块(5级)

2)当密码不显示无效密码失败/错误的身份验证方法的返回值时: let(:user_for_invalid_password) {found_user.authenticate(“无效”)} NoMethodError:未定义方法authenticate' for nil:NilClass # ./spec/models/user_spec.rb:98:in块(5个级别)在‘#./spec/model/ User _spec.rb:100:100: in’block (5级) in‘

3)当密码不显示无效密码失败/错误的身份验证方法的返回值时: let(:user_for_invalid_password) {found_user.authenticate(“无效”)} NoMethodError:未定义方法authenticate' for nil:NilClass # ./spec/models/user_spec.rb:98:in块(5个级别)在‘#./spec/model/ User _spec.rb:101: in’block(5个级别)‘中

User_spec试验

要求'spec_helper‘

代码语言:javascript
复制
describe User do

  before do 
    @user = User.new(name: "Example User", email: "user@example.com",
                      password: "foobar", password_confirmation: "foobar")
  end


  subject { @user }

  it { should respond_to(:name) }
  it { should respond_to(:email) }
  it { should respond_to(:password_digest) }
  it { should respond_to(:password) }
  it { should respond_to(:password_confirmation) }
  it { should respond_to(:authenticate) }

  it { should be_valid }

  describe "when name is not present" do
    before { @user.name = " " }
    it { should_not be_valid }
  end

  it "should be valid" do
    expect(@user).to be_valid
  end

  describe "when email is not present" do
    before { @user.email = " " }
    it { should_not be_valid }
  end

  describe "when name is too long" do
    before { @user.name = 'a' * 51 }
    it { should_not be_valid }
  end

  describe "when email format is invalid" do
  it "should be invalid" do
    addresses = %w[user@foo,com user_at_foo.org example.user@foo.
                   foo@bar_baz.com foo@bar+baz.com]
    addresses.each do |invalid_address|
      @user.email = invalid_address
      expect(@user).not_to be_valid
    end
  end
end

describe "when email format is valid" do
  it "should be valid" do
    addresses = %w[user@foo.COM A_US-ER@f.b.org frst.lst@foo.jp a+b@baz.cn]
    addresses.each do |valid_address|
      @user.email = valid_address
      expect(@user).to be_valid
    end
  end
end

describe "when email address is already taken" do
  before do
    user_with_same_email = @user.dup
    user_with_same_email.email = @user.email.upcase
    user_with_same_email.save
  end

  it { should_not be_valid }
  end

  describe "when password is not present" do
    before do
      @user = User.new(name:"Example User", email: "user@example.com",
                        password: " ", password_confirmation: " ")
    end
    it { should_not be_valid }


  describe "when password does not match confirmation" do
    before { @user.password_confirmation = "mismatch" }
    it { should_not be_valid }
  end

  describe "with a password thats too short" do
    before { @user.password = @user.password_confirmation = "a" * 5 }
    it { should be_invalid }
  end

  describe "return value of authenticate method" do
  before { @user.save }
  let(:found_user) { User.find_by(email: @user.email) }

  describe "with valid password" do
    it { should eq found_user.authenticate(@user.password) }
  end

  describe "with invalid password" do
    let(:user_for_invalid_password) { found_user.authenticate("invalid") }

    it { should_not eq user_for_invalid_password }
    specify { expect(user_for_invalid_password).to be_false }
  end
end

端端

用户模型

代码语言:javascript
复制
class User < ActiveRecord::Base 
  before_save { self.email = email.downcase }
  validates :name, presence: true, length: { maximum: 50 }
  VALID_EMAIL_REGEX = /\A[\w+\-.]+@[a-z\d\-.]+\.[a-z]+\z/i
  validates :email, presence: true, format: { with: VALID_EMAIL_REGEX },
                    uniqueness: { case_sensitive: false }
  has_secure_password
  validates :password, length: { minimum: 6 }

end
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2014-03-07 20:10:20

您将得到错误,因为found_user为零。

这是因为您没有正确地关闭when password is not present描述块。因此,这个无效的@user是用一个空白密码设置的,它被转发到失败的测试用例。

代码语言:javascript
复制
  describe "when password is not present" do
    before do
      @user = User.new(name:"Example User", email: "user@example.com",
                       password: " ", password_confirmation: " ")
    end
    it { should_not be_valid }
  end  ### Add end here

另外,从文件底部删除最后一个end

票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/22259668

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