扫桩发生器

Question

我是个新手，正为这个循环问题而发狂。我想随机地把一个国家分配给参加抽奖比赛的人的名单。一旦一个国家被分配了，那么它就不再可以在循环的进一步迭代中被分配。循环应该遍历整个人员列表(这比国家列表要短)。是的，我知道代码可能更简单，但这正是我放弃的时候。请指点！

import random
filez = open ('C:/Users/Andy/Desktop/countrys.txt', 'r')
countries = filez.readlines()

filez2 = open ('C:/Users/Andy/Desktop/names.txt', 'r' )
people = filez2.readlines()

def chop (x):    #gets rid of wierd added bits
    for i in range(0, len(x)):
        x[i] = x[i] [:-1]
    return x

chop(countries)
chop(people)

def assign (y):
    used = []
    for person in range(0, len(y)):
        num = random.randint(0, len(countries))    
        if num not in used:
            print (people[person] + " gets " + countries[num])
            used.append(num)
        else:
            num = random.randint(0, len(countries))
            print (people[person] + " gets " + countries[num])
            used.append(num)


assign(people)

Answer 1

一个可能的解决办法是：

random.shuffle(countries)
assignments = list(zip(people, countries))

这将给出一个(person, country)元组的列表。