为什么两个Java对象都返回相同的数据

Question

我已经创建了类GConveyor的两个对象。我希望在选择对象时获得一些有关对象的数据，但两者返回相同的信息。谢谢你的帮助！

/* 
* File: DragObjects.java  
*/ 
import acm.graphics.*; 
import acm.program.*; 
import java.awt.event.*;

public class DragObjects extends GraphicsProgram { 
private static final long serialVersionUID = 1L;
// Initializes the program 
public void init() { 
    //adding a few test objects
    GConveyor conv = new GConveyor(50, 44, 120); 
    add(conv); 
    GConveyor conv2 = new GConveyor(30, 24, 60); 
    add(conv2); 

    addMouseListeners(); 
    addKeyListeners(); 
    } 

// Called on mouse press to record the coordinates of the click */ 
public void mousePressed(MouseEvent e) { 
    // GPoint has X and Y coordinate 
    last = new GPoint(e.getPoint()); 
    gobj = getElementAt(last);  
    //looking at stuff so to understand
    getObjectData ();
}


public void getObjectData (){
    //looking at stuff so to understand
    System.out.println(gobj.toString());    

    GContainer obLength = gobj.getParent();
    System.out.println(obLength.toString());    

    int d = ((GCompound) gobj).getElementCount();
    System.out.println( "Element per GConveyor:"+ d  );

    System.out.println( "hashcode:" +gobj.hashCode());

    int y = this.getElementCount();
    System.out.println( "this Element Count:"+ y  );

    int a = GConveyor.getBF();      
    System.out.println( "bf:" + a  );
    int b = GConveyor.getEF();      
    System.out.println( "ef:" + b  );
    int h = GConveyor.getLength();      
    System.out.println( "length:" + h  );
    int c = ((GConveyor) gobj).getLength();     
    System.out.println( "length:" + c  );       
}



// Called on mouse drag to reposition the object 
public void mouseDragged(MouseEvent e) { 
    if (gobj != null) { 
        gobj.move(e.getX() - last.getX(), e.getY() - last.getY()); 
        last = new GPoint(e.getPoint());
        } } 

/* Private instance variables */
private GObject gobj; 
/* The object being dragged */
private GPoint last; 

}

下面是我的GConveyor类

 /* 
 * 
 * File: GConveyor.java * This class implements a conveyor as a GCompound.
 */ 

import java.awt.Color;
import acm.graphics.*; 

public class GConveyor extends GCompound {
/* Constants specifying frame size*/
private static final int FRAME_WIDTH = 2;
private static int myBf;
private static int myEf;
private static int myLength;

private static final double scale = 10;
/* Private instance variables */
private GRect outer;
private GRect chain_box;
private GRect effWidth;
private GPolygon pti;
private GPolygon pto;

public GConveyor(int bf, int ef, int length) {
outer = new GRect(length, ((FRAME_WIDTH *2) + bf));
chain_box = new GRect(length , bf - ef);
effWidth = new GRect(length, bf);
pti = createAnchor(scale);
pto = createAnchor(scale);
add(outer, 0 , 0);
add(chain_box, 0 , FRAME_WIDTH);
add(effWidth, 0 , FRAME_WIDTH);
add(pti, 0 , FRAME_WIDTH + (bf-ef) + (ef/2));
add(pto, length , FRAME_WIDTH + (bf-ef) + (ef/2));

myBf = bf;
myEf = ef;
myLength = length;

}

public static int getBF(){
return myBf;
}
public static int getEF(){
return myEf; 
}
public static int getLength(){
return myLength;
}


/* Creates a hex for the Anchor */
private GPolygon createAnchor(double scale) {
GPolygon poly = new GPolygon();
poly.addVertex(-0.25*scale, 0.433*scale);
poly.addVertex(-0.5*scale, 0.0*scale);
poly.addVertex(-0.25*scale, -0.433*scale);
poly.addVertex(0.25*scale, -0.433*scale);
poly.addVertex(0.5*scale, 0.0*scale);
poly.addVertex(0.25*scale, 0.433*scale);
poly.setFilled(true);
poly.setFillColor(Color.BLUE);
return poly;
}

public String toString(){
return("" +myBf+ +myEf+ +myLength+ "");

}

}

Answer 1

这些变量是静态的，因此这些单变量(及其奇异值)将在GConveyor类的所有实例中使用。这就是为什么你会得到同样的信息。

private static final int FRAME_WIDTH = 2;
private static int myBf;
private static int myEf;
private static int myLength;

如果您不需要static关键字(在每个实例中都需要唯一的信息)，那么您应该做得很好。

Answer 2

myBF、myEF和myLength在GConveyor中被声明为static。这意味着每个整数中只有一个，每个整数都由类的所有对象共享。当调用GConveyor构造函数来创建第二个实例时，构造函数设置这些静态字段，然后影响第一个实例返回的值。

Answer 3

您的toString()发出了myBf myEf和myLength，它们都是静态的。这意味着它们是类本身(of GConveyer)的属性，而不是类的实例(conv和conv2)的属性，所以当您为其中任何一个调用实例的setter方法时，您将修改相同的变量。

您有两个实例，但只有一个类，所以您只有1组这些变量，而不是2个。

如果希望将它们归因于每个实例，而不是整个类，请不要使它们是静态的。