在python字典中查找术语

Question

如果我有一张口袋妖怪的清单：

not_e =     {"Bulbasaur": ["Overgrow", "Tackle", "Leech Seed"],
                  "Charmander": ["Blaze", "Scratchy", "Growl"],
                  "Squirtle": ["Torrent", "Tackle", "Tail Whip"],
                  "Pikachu": ["Static", "Tail Whip", "Thunder Shock"],
                  "Haunter": ["Levitate", "Hypnosis", "Spite"],}

如果我想选择一个随机的口袋妖怪，我就是这样做的：

random_pokemon = ["Bulbasaur", "Charmander", "Squirtle", "Pikachu", "Haunter"] 
rand_pokemon = random.choice(random_pokemon) 
print("Your pokemon is: " + rand_pokemon)

我将如何在字典中搜索随机的口袋妖怪，并从中获取能量列表？

Answer 1

# this randomly selects the character.
character = random.choice(not_e.keys())

# this prints the powers of the randomly selected characters.
print not_e[character]

如果您想要的只是随机选择的口袋妖怪字符的功能，您可以组合这两个语句，如下所示

print not_e[random.choice(not_e.keys())]

Answer 2

如果要以更方便用户的格式打印权限列表，请使用：

print ' '.join(not_e[character])

这将打印由空格分隔的所有能量。如果要用新行分隔它们，请使用

print '\n'.join(not_e[character])