我已经在这个问题上寻找了一个答案,但没有结果,有一个类似的问题,但在这种情况下答案无效,它对一个数字项进行排序。Similar Question -That did not work,我正在尝试使用ruby的sort_by来排序一个项目下降和另一个升序。我只能找到一个或另一个。
以下是代码:
# Primary sort Last Name Descending, with ties broken by sorting Area of interest.
people = people.sort_by { |a| [ a.last_name, a.area_interest]}任何指导都肯定会有所帮助。
样本数据:
输入
输出
发布于 2014-03-01 19:38:28
创建一个自定义类,反转<=>的结果(包括Comparable)。
用自定义类包装要降序排序的对象。
示例:
class Descending
include Comparable
attr :obj
def initialize(obj)
@obj = obj
end
def <=>(other)
return -(self.obj <=> other.obj)
end
end
people = [
{last_name: 'Russell', area_interest: 'Logic'},
{last_name: 'Euler', area_interest: 'Graph Theory'},
{last_name: 'Galois', area_interest: 'Abstract Algebra'},
{last_name: 'Gauss', area_interest: 'Number Theory'},
{last_name: 'Turing', area_interest: 'Algorithms'},
{last_name: 'Galois', area_interest: 'Logic'},
]
puts people.sort_by {|person| [
Descending.new(person[:last_name]), # <---------
person[:area_interest],
]}产出:
{:last_name=>"Turing", :area_interest=>"Algorithms"}
{:last_name=>"Russell", :area_interest=>"Logic"}
{:last_name=>"Gauss", :area_interest=>"Number Theory"}
{:last_name=>"Galois", :area_interest=>"Abstract Algebra"}
{:last_name=>"Galois", :area_interest=>"Logic"}
{:last_name=>"Euler", :area_interest=>"Graph Theory"}顺便说一句,如果您希望排序降序的对象是一个数值,您可以简单地使用一元运算符-。
people.sort_by {|person| [-person.age, person.name] }发布于 2014-03-02 06:22:49
这是一个直截了当的方法:
a = [ ['Russell', 'Logic'], ['Euler', 'Graph Theory'],
['Galois', 'Abstract Algebra'], ['Gauss', 'Number Theory'],
['Turing', 'Algorithms'], ['Galois', 'Logic'] ]
a.sort { |(name1,field1),(name2,field2)|
(name1 == name2) ? field1 <=> field2 : name2 <=> name1 }
#=> [ ["Turing", "Algorithms"], ["Russell", "Logic"],
# ["Gauss", "Number Theory"], ["Galois", "Abstract Algebra"],
# ["Galois", "Logic"], ["Euler", "Graph Theory"] ]对于多个字段,先按降序排序,然后依次对其他字段按升序排序:
a = [ %w{a b c}, %w{b a d}, %w{a b d}, %w{b c a}, %w{a b c}, %w{b c b}]
#=> [["a", "b", "c"], ["b", "a", "d"], ["a", "b", "d"],
# ["b", "c", "a"], ["a", "b", "c"], ["b", "c", "b"]]
a.sort { |e,f| e.first == f.first ? e[1..-1] <=> f[1..-1] : f <=> e }
#=> [["b", "a", "d"], ["b", "c", "a"], ["b", "c", "b"],
# ["a", "b", "c"], ["a", "b", "c"], ["a", "b", "d"]] https://stackoverflow.com/questions/22119121
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