减速物体？

Question

我有一个Sphere对象从屏幕顶部掉下来(Sphere位置y= 5)。我有一个"isTrigger = true“和"Mesh renderer = false”的立方体，位置为"y = 0.5“(0.5 =立方体的中心)。你看不见立方体。

球体现在正在下落。现在我想，当球体接触到立方体时，球体正在减速到零(没有反转)。我想要一个衰减/阻尼。

我尝试了这个例子但没有成功：http://docs.unity3d.com/Documentation/ScriptReference/Vector3.SmoothDamp.html

// target = sphere object 
public Transform target;

public float smoothTime = 0.3F;
private Vector3 velocity = Vector3.zero;
private bool slowDown = false;


void Update () {
if (slowDown) {
    Vector3 targetPosition = target.TransformPoint(new Vector3(0, 0, 0));
            transform.position = Vector3.SmoothDamp(transform.position, targetPosition, ref velocity, smoothTime);
}   

}



void OnTriggerEnter(Collider other) {
if (other.name == "Sphere") {
    slowDown = true;
}
}

脚本被附加到多维数据集。

Answer 1

您可能需要尝试这种方法：

// We will multiply our sphere velocity by this number with each frame, thus dumping it
public float dampingFactor = 0.98f;
// After our velocity will reach this threshold, we will simply set it to zero and stop damping
public float dampingThreshold = 0.1f;

void OnTriggerEnter(Collider other)
{
    if (other.name == "Sphere")
    {
        // Transfer rigidbody of the sphere to the damping coroutine
        StartCoroutine(DampVelocity(other.rigidbody));
    }
}

IEnumerator DampVelocity(Rigidbody target)
{
    // Disable gravity for the sphere, so it will no longer be accelerated towards the earth, but will retain it's momentum
    target.useGravity = false;

    do
    {
        // Here we are damping (simply multiplying) velocity of the sphere whith each frame, until it reaches our threshold 
        target.velocity *= dampingFactor;
        yield return new WaitForEndOfFrame();
    } while (target.velocity.magnitude > dampingThreshold);

    // Completely stop sphere's momentum
    target.velocity = Vector3.zero;
}

我在这里假设你有一个刚体在你的球体上，它正在下降到‘自然’重力(如果不是--只是在你的球体中添加刚体组件，不需要进一步调整)，如果不是，你很熟悉协同--看看这个手册：http://docs.unity3d.com/Documentation/Manual/Coroutines.html

如果使用得当，协同服务可能会很有帮助:)