php下拉菜单中选择的耳聋值

Question

我正在处理一个PHP项目，如下所示

 if( mysql_num_rows( $result ) > 0 ) {
    echo '<select name="officerlist">';
    while ( $rows = mysql_fetch_array ( $result ) ) {                       
       echo '<option>' . $rows['officer'] . '</option>';
       if ($types[ $maxindex ] == $rows['officer']){
        echo ' selected';
       }
    }
        echo '</select>';
}

我能够将查询结果填充到下拉菜单中。但是，我希望将其实现为基于来自另一个数组的值的默认值。(即如果在$ $types$maxindex中找到了“军官”，它将自动选择该值。)

有人能给我建议吗？

谢谢，并致以最良好的问候！

Answer 1

应该是这样，

while ( $rows = mysql_fetch_array ($result) ) {                       

    if ($types[$maxindex] == $rows['officer']){
        echo '<option selected="selected" value="'.$rows['officer'].'">' . $rows['officer'] . '</option>';
    } else {
       echo '<option value="'.$rows['officer'].'">' . $rows['officer'] . '</option>';
    }
   }

Answer 2

尝尝这个

if( mysql_num_rows($result)>0 ) {
echo '<select name="officerlist">';
while ( $rows = mysql_fetch_array ($result) ) {                       
if ($types[$maxindex] == $rows['officer']){
    echo '<option selected="selected">' . $rows['officer'] . '</option>';    
}
else
{
    echo '<option>' . $rows['officer'] . '</option>';

}
}
echo '</select>';

Answer 3

您需要在selected标记中添加<option>属性，如

<option selected='selected'>youroption</option>。

尝尝这个,

if( mysql_num_rows($result)>0 ) {
    echo '<select name="officerlist">';
    while ( $rows = mysql_fetch_array ($result) ) {
        $selected ="";
        if ($types[$maxindex] == $rows['officer']){
            $selected = ' selected="selected" ';
        }
        echo '<option '.$selected.'>' . $rows['officer'] . '</option>';

    }
    echo '</select>';
}