代码:
MYSQL *con = mysql_init(NULL);
MYSQL_RES* result;
MYSQL_ROW row;
void student_login(string enrollno,string passwd)
{
if(mysql_query(con,"SELECT * FROM user_student WHERE ENROLLMENTNO='enrollno' "))
{
finish_with_error(con);
}
result=mysql_store_result(con);
if(result==NULL)
finish_with_error(con);
int num_fields=mysql_num_fields(result);
while ((row = mysql_fetch_row(result)))
{
for(int i = 0; i < num_fields; i++)
{
printf("%s ", row[i] ? row[i] : "NULL");
}
printf("\n");
}
cout<<" i m done";
}数据库:
`enrollmentno password`我收到了访问违规的错误。当我使用断点进行调试时,问题似乎是在mysql_fetch_row函数中。
发布于 2014-02-19 19:10:46
你已经用过两次row=mysql_fetch_row(result);了。
删除这一行row=mysql_fetch_row(result);
https://stackoverflow.com/questions/21889948
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