如何找出列中2行间的时间差

Question

嗨，当我使用这个查询时，它会给我一个2列，每一行都会有一个请求和一个响应。我怎么用秒来计算这两者之间的时间差呢？

select M.MSG_DESC, M.Msg_Ts from INTLOG.ESB_MSG_L M,INTLOG.ESB_PAYLOAD_L P
where M.MSG_ID = P.MSG_ID
And M.Msg_Ts >= Timestamp'2014-02-16 00:00:00' 
And M.Msg_Ts <= Timestamp'2014-02-17 12:00:00' 
And M.Msg_ID IN ('90808','67678','534534')
ORDER by M.MSG_TS,p.payload_corl_id desc;

DatabaseUtility请求内部18-2月14日01.00.10.569000000 PM DatabaseUtility响应内部18-2月14日01.00.19.553000000 PM DatabaseUtility请求内部18-2月14日01.00.29.146000000 PM DatabaseUtility响应内部18-2月14日01.00.29.705000000 PM DatabaseUtility请求内部18-2月14日01.00.35.278000000 PM DatabaseUtility响应内部18-2月14日01.00.38.313000000 PM

Answer 1

select M.MSG_DESC
     , M.Msg_Ts 
     ,TIMESTAMPDIFF(SECOND, M.MSG_DESC, M.Msg_Ts )
from INTLOG.ESB_MSG_L M INNER JOIN INTLOG.ESB_PAYLOAD_L P
ON   M.MSG_ID = P.MSG_ID
WHERE
    M.Msg_Ts >= Timestamp'2014-02-16 00:00:00' 
And M.Msg_Ts <= Timestamp'2014-02-17 12:00:00' 
And M.Msg_ID IN ('90808','67678','534534')
ORDER by M.MSG_TS,p.payload_corl_id desc;