我使用iOS上的Xamarin +iOS浏览网络上的web服务器,然后从网络中下载文件。
传递给“解决”事件处理程序的NSNetService包含作为NSData的地址。我找不到一种很好的方法将这个NSData转换成一个实际的IP地址,然后我可以从它构建一个网址,即http:// < IPAddress >/IPAddress/file.htm。
这是我的NSNetService.AddressResolved事件处理程序:
private void OnServiceResolved(object sender, EventArgs args)
{
NSNetService service = (NSNetService)sender;
// service.Port is valid.
// service.HostName is valid.
// but we want the IP addres, which is in service.Addresses.
// None of the following four methods works quite right.
IPAddress address = (IPAddress)service.Addresses [0]; // Cannot convert type NSData to IPAddress
SocketAddress address2 = (SocketAddress)service.Addresses[0]; // Cannot convert NSData to SocketAddress. A binary copy might work?
IPHostEntry entry = (IPHostEntry)service.Addresses [0]; // Cannot convert NSData to IPHostEntry
IPHostEntry entry2 = Dns.GetHostByName (service.HostName); // This kinda works, but is dumb. Didn't we just resolve?
}在解析事件中从NSNetService获取服务IP地址的正确方法是什么?
发布于 2014-02-22 17:45:05
NSNetService.Addresses属性提供NSData实例,这些实例必须转换为IPAddress (或其他.NET类型)可以消化的内容。例如。
MemoryStream ms = new MemoryStream ();
(ns.Addresses [0] as NSData).AsStream ().CopyTo (ms);
IPAddress ip = new IPAddress (ms.ToArray ());请注意,这可以返回IPv6地址(或IPAddress不接受的格式)。您可能需要迭代所有的Addresses以找到最好的一个。
我将考虑在Xamarin.iOS的未来版本中添加一种方便的方法。
更新
返回一个IPAddress的更完整的版本如下所示:
static IPAddress CreateFrom (NSData data)
{
byte[] address = null;
using (MemoryStream ms = new MemoryStream ()) {
data.AsStream ().CopyTo (ms);
address = ms.ToArray ();
}
SocketAddress sa = new SocketAddress (AddressFamily.InterNetwork, address.Length);
// do not overwrite the AddressFamily we provided
for (int i = 2; i < address.Length; i++)
sa [i] = address [i];
IPEndPoint ep = new IPEndPoint (IPAddress.Any, 0);
return (ep.Create (sa) as IPEndPoint).Address;
}https://stackoverflow.com/questions/21743679
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