字符串中的解析日期

Question

我有这样的字符串：

Available. Released 2013, November

我正在寻找一种方法来获取:年份，月份

到目前为止我有这样的判断力：

/Released \b\d{4}\b,\s?/.match('Released 2013, ')

但我却看不出我会怎么度过这个月？

Answer 1

使用String#scan和捕获组：

text = <<EOS
Available. Released 2013, November
Available. Released 2012, October
EOS

text.scan(/Released\s+(\d{4},\s*[A-Z][a-z]+)/)
# => [["2013, November"], ["2012, October"]]

text.scan(/Released\s+(\d{4}),\s*([A-Z][a-z]+)/)
# => [["2013", "November"], ["2012", "October"]]

更新

如果只希望第一次匹配，请使用String#[]

text[/Released\s+\d{4},\s*[A-Z][a-z]+/]
# => "Released 2013, November"
text[/Released\s+(\d{4},\s*[A-Z][a-z]+)/, 1]
# => "2013, November"

Answer 2

s = <<_
Available. Released 2013, November
Available. Released 2012, October
_

s.each_line.map{|s| s.split("Released").last.strip}
# => ["2013, November", "2012, October"]

"Available. Released 2013, November".split("Released ").last
# => "2013, November"

Answer 3

我会使用CSV::parse：

require 'csv'

text = <<EOS
Available. Released 2013, November
Available. Released 2012, October
EOS

ary = CSV.parse(text,:col_sep => " ").map do |a|
  a.last(2).join(" ")
end

ary # => ["2013, November", "2012, October"]