阿迪诺旋律循环？

Question

这是我的代码，一切都很好，除了我不知道如何得到我创造的旋律循环？另一个问题是，我如何使LED同时闪烁的旋律播放？

#include "pitches.h"

int led = 9;

int melody[] = {
    NOTE_C4, NOTE_G3,NOTE_G3, NOTE_A3, NOTE_G3,0, NOTE_B3, NOTE_C4
};

int noteDurations[] = { 4, 8, 8, 4,4,4,4,4 };

void setup() {
    pinMode(led, OUTPUT);    

    // iterate over the notes of the melody:
    for (int thisNote = 0; thisNote < 8; thisNote++) {

        // to calculate the note duration, take one second 
        // divided by the note type.
        //e.g. quarter note = 1000 / 4, eighth note = 1000/8, etc.
        int noteDuration = 1000/noteDurations[thisNote];
        tone(8, melody[thisNote],noteDuration);

        // to distinguish the notes, set a minimum time between them.
        // the note's duration + 30% seems to work well:
        int pauseBetweenNotes = noteDuration * 1.30;
        delay(pauseBetweenNotes);
        // stop the tone playing:
        noTone(8);
    }
}

void loop() {
    digitalWrite(led, HIGH);   // turn the LED on (HIGH is the voltage level)
    delay(1000);               // wait for a second
    digitalWrite(led, LOW);    // turn the LED off by making the voltage LOW
    delay(1000);
}

Answer 1

只需将代码放在独立的函数中，然后从循环中调用它：

#include "pitches.h"

int led = 9;

int melody[] = {
    NOTE_C4, NOTE_G3,NOTE_G3, NOTE_A3, NOTE_G3,0, NOTE_B3, NOTE_C4
};

int noteDurations[] = { 4, 8, 8, 4,4,4,4,4 };

void play_melody();

void setup() {
    pinMode(led, OUTPUT);    
}

void loop() {
    digitalWrite(led, HIGH);   // turn the LED on (HIGH is the voltage level)
    // keep the LED on while the melody's playing
    play_melody(); 
    digitalWrite(led, LOW);    // turn the LED off by making the voltage LOW
    // pause for one second between each melody iteration (you can remove this for continuous playing)
    delay(1000);
}

void play_melody() {
    // iterate over the notes of the melody:
    for (int thisNote = 0; thisNote < 8; thisNote++) {

        // to calculate the note duration, take one second 
        // divided by the note type.
        //e.g. quarter note = 1000 / 4, eighth note = 1000/8, etc.
        int noteDuration = 1000/noteDurations[thisNote];
        tone(8, melody[thisNote],noteDuration);

        // to distinguish the notes, set a minimum time between them.
        // the note's duration + 30% seems to work well:
        int pauseBetweenNotes = noteDuration * 1.30;
        delay(pauseBetweenNotes);
        // stop the tone playing:
        noTone(8);
    }
    return;
}

如果您不知道函数调用，我建议您打开一个C语言书籍，如K&R，并阅读它，您可以在其中学习C语言编程的基础知识。

Answer 2

在循环()內播放音樂，同時；在Timer中斷程式回调()內控制內控制閃爍例:Timer1.attachInterruption(回调)；

在循环()函数中播放旋律，同时在计时器交互功能中闪烁LED。例:Timer1.attachInterruption(回调)；