blocks|key|939245|text|从我对行动的评论来看..。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|939246|这意味着你已经用光了谷歌的配额。|939247|您是否已设置自己的Api密钥，并检查您是否超过了您的津贴？我猜它是在引擎盖下面使用这项服务。|offset|length|939248|注:如果有其他人使用该服务(大学、同一家公司等)拥有相同的公共IP，而您没有使用API密钥，这可能说明您得到的免费使用少于2500次。|939249|entityMap|0|LINK|mutability|MUTABLE|url|https://developers.google.com/maps/documentation/geocoding/#Limits^0|0|0|15|4|0|0|0^^$0|@$1|2|3|4|5|6|7|R|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|S|8|@]|9|@]|A|$]]|$1|D|3|E|5|6|7|T|8|@]|9|@$F|U|G|V|1|W]]|A|$]]|$1|H|3|I|5|6|7|X|8|@]|9|@]|A|$]]|$1|J|3|-4|5|6|7|Y|8|@]|9|@]|A|$]]]|K|$L|$5|M|N|O|A|$P|Q]]]]

From my comments on the OP...

This implies that you've used up your quota from Google.

Have you set up your own Api key and checked that you're not exceeding your allowance? I assume it's using <a href="https://developers.google.com/maps/documentation/geocoding/#Limits" rel="nofollow noreferrer">this service</a> under the hood.

NB: If there's someone else with the same public IP using the service (University, Same company, etc) and you're not using an API key, that might account for you getting less than the 2,500 free uses.

blocks|key|939295|text|有一个API列表，并对每个请求随机使用它们。例如，在python中|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|939296|like+keys+=+[key1,key1,key3....]

location+=+Geocoder(random.choice(keys)).geocode(address)+|code-block|syntax|javascript|939297|或|939298|location+=+Geocoder(random.choice(keys)).reverse_geocode(Lat,Long)|939299|根据你的要求。你的零用钱会更多。|939300|entityMap^0|Q|6|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|S|8|@$9|T|A|U|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|V|8|@]|D|@]|E|$I|J]]|$1|K|3|L|5|6|7|W|8|@]|D|@]|E|$]]|$1|M|3|N|5|H|7|X|8|@]|D|@]|E|$I|J]]|$1|O|3|P|5|6|7|Y|8|@]|D|@]|E|$]]|$1|Q|3|-4|5|6|7|Z|8|@]|D|@]|E|$]]]|R|$]]

Have a list of API's and use them randomly for each request. For Example in <code>python</code>:

<pre><code>like keys = [key1,key1,key3....]

location = Geocoder(random.choice(keys)).geocode(address) 
</code></pre>

or

<pre><code>location = Geocoder(random.choice(keys)).reverse_geocode(Lat,Long)
</code></pre>

Based on your Requirement. Your allowance would be more.

blocks|key|216455|text|作为一种临时解决方案，您可以使用VPN+(这将为您提供另一组2500个免费请求)。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|216456|带有随机键的解决方案也应该可以工作，而且它更适合永久使用，但是如果您只是在测试过程中(这就是我的情况)，这是一个快速的解决方案。|216457|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|F|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|G|8|@]|9|@]|A|$]]|$1|D|3|-4|5|6|7|H|8|@]|9|@]|A|$]]]|E|$]]

As a temporary solution, you can use VPN (which gives you another set of 2 500 requests for free).

Solution with random keys should work as well and it is better for permanent use but if you are just in process of testing (which was my case), this is a quick solution.

blocks|key|1217929|text|编辑:截至2018年7月，我发现每个API键的默认请求是每天1次。因此，你必须在你的谷歌云平台注册一个计费帐户，以获得每天大约1000次的免费请求。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1217930|注册您自己的API是个不错的选择！@Yaswanth的回答对我来说不太管用，但是从这里到现在：https://github.com/geopy/geopy，确实如此：|offset|length|1217931|步骤1.在这里注册私钥：https://developers.google.com/maps/documentation/geolocation/intro|1217932|步骤2.在您的python中，导入一个好的Geo编码器，我推荐GoogleV3。|1217933|from+geopy.geocoders+import+GoogleV3|code-block|syntax|javascript|1217934|步骤3.然后在您的代码中，输入您在上面的链接中注册的多少个密钥。|1217935|address+=+'1+Your+Address+Here'+#+Put+in+your+address
geo_keys+=+[key1,key1,key3....]+#+Put+in+your+API+keys+as+strings
geolocator+=+GoogleV3(+api_key=random.choice(geo_keys)+)
geolocator.geocode(+address+)|1217936|第四步。那你就做生意了！|1217937|print(geolocator.latitude)
print(geolocator.longitude)|1217938|entityMap|0|LINK|mutability|MUTABLE|url|https://github.com/geopy/geopy|1|https://developers.google.com/maps/documentation/geolocation/intro^0|0|1B|U|0|0|C|1U|1|0|0|0|0|0|0|0^^$0|@$1|2|3|4|5|6|7|16|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|17|8|@]|9|@$D|18|E|19|1|1A]]|A|$]]|$1|F|3|G|5|6|7|1B|8|@]|9|@$D|1C|E|1D|1|1E]]|A|$]]|$1|H|3|I|5|6|7|1F|8|@]|9|@]|A|$]]|$1|J|3|K|5|L|7|1G|8|@]|9|@]|A|$M|N]]|$1|O|3|P|5|6|7|1H|8|@]|9|@]|A|$]]|$1|Q|3|R|5|L|7|1I|8|@]|9|@]|A|$M|N]]|$1|S|3|T|5|6|7|1J|8|@]|9|@]|A|$]]|$1|U|3|V|5|L|7|1K|8|@]|9|@]|A|$M|N]]|$1|W|3|-4|5|6|7|1L|8|@]|9|@]|A|$]]]|X|$Y|$5|Z|10|11|A|$12|13]]|14|$5|Z|10|11|A|$12|15]]]]

EDIT: As of July 2018, I'm finding the default requests per API key is 1 per day. 
 So you have to register a billing account with your google cloud platform to get the free approx 1000 requests per day.

Registering for your own API is a good move! @Yaswanth's answer didn't quite work for me, but from that and here: <a href="https://github.com/geopy/geopy" rel="nofollow noreferrer">https://github.com/geopy/geopy</a>, this does:

Step 1. Register for your private keys here: <a href="https://developers.google.com/maps/documentation/geolocation/intro" rel="nofollow noreferrer">https://developers.google.com/maps/documentation/geolocation/intro</a>

Step 2. In your python, import a good geocoder, I recommend GoogleV3.

<pre><code>from geopy.geocoders import GoogleV3
</code></pre>

Step 3. then in your code, put in however many keys you have registered in that link above.

<pre><code>address = '1 Your Address Here' # Put in your address
geo_keys = [key1,key1,key3....] # Put in your API keys as strings
geolocator = GoogleV3( api_key=random.choice(geo_keys) )
geolocator.geocode( address )
</code></pre>

Step 4. Then you're in business!

<pre><code>print(geolocator.latitude)
print(geolocator.longitude)
</code></pre>

I just started using GeoPy. I need to convert a given location to latitude and longitude. However I am getting a GeocoderQuotaExceeded error. I just followed the example given in the documentation. Any help would be greatly appreciated.

<pre><code>from geopy.geocoders import GoogleV3
geolocator = GoogleV3()
address, (latitude, longitude) = geolocator.geocode("175 5th Avenue NYC")
GeocoderQuotaExceeded: The given key has gone over the requests limit in the 24 hour period or has submitted too many requests in too short a period of time
</code></pre>

This happened on the first request itself. i had not made any other requests ever. This was the first time I was using the application.

GeoPy: GeocoderQuotaExceeded error

翻译质量差，导致语言生硬或混乱。

没有提供实际的解决方法或示例。

解答不清晰，无法理解或解决问题。

页面排版不美观，阅读体验差。

文章

问答

视频

教程

学习中心

腾讯云实验室

直播

竞赛

腾讯云代码分析专区

腾讯iOA零信任安全管理系统专区

腾讯云架构师技术同盟交流圈

腾讯云数据库专区

腾讯云智能顾问专区

腾讯云原生专区

腾讯混元专区

腾讯云TCE专区

腾讯云Lighthouse专区

腾讯云HAI专区

腾讯云Edgeone专区

腾讯云存储专区

腾讯云智能专区

腾讯轻联专区 

腾讯云开发专区

TAPD专区

腾讯轻量云游戏服专区

腾讯云最具价值专家

腾讯云架构师技术同盟

腾讯云创作之星

腾讯云开发者先锋

腾讯云AI代码助手

云原生构建

TAPD 敏捷项目管理

Cloud Studio

SDK中心

API中心

命令行工具

功能1上新10个字符

功能2描述100个字符功能2描述100个字符功能2描述100个字符功能2描述100个字符功能2描述100个字符功能2描述100个字符功能2描述100个字符功能2描述100个字符功能2描述100个字符。

功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符功能2上新100个字符。

功能5描述100个字符功能5描述100个字符功能5描述100个字符功能5描述100个字符功能5描述100个字符功能5描述100个字符

功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符功能5上新100个字符

功能4上新

文章&问答评论现已支持表情

全新交互，全新视觉，新增快捷键、悬浮工具栏、高亮块等功能并同时优化现有功能，全面提升创作效率和体验

社区富文本编辑器全新改版！诚邀体验～ 

精选全网热门MCP server，让你的AI更好用 🚀

💥开发者 MCP广场重磅上线！

涵盖代码开发、场景应用、自动测试全流程，助你从零构建专属AI助手

一站式MCP教程库，解锁AI应用新玩法

聚焦“写作效率、视觉美观与运行性能”三方面进行全面升级，为您提供更高效、稳定的创作环境

社区富文本&Markdown编辑器全新改版上线，欢迎大家体验!

诚挚邀请您参与本次调研，分享您的真实使用感受与建议。您的反馈至关重要，感谢您的支持与参与！

社区新版编辑器体验调研

我刚刚开始使用GeoPy。我需要把给定的位置转换成经纬度。但是，我得到了一个GeocoderQuotaExceeded错误。我只是遵循了文档中给出的例子。任何帮助都将不胜感激。from geopy.geocoders import GoogleV3geolocator = GoogleV3()address, (latitude, longitude) = geolocator.geocode("

问GeoPy: GeocoderQuotaExceeded错误
EN

回答 4

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问GeoPy: GeocoderQuotaExceeded错误EN

回答 4

Stack Overflow用户

Stack Overflow用户

Stack Overflow用户

社区

活动

圈层

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

问GeoPy: GeocoderQuotaExceeded错误
EN