FOSUserBundle中的自定义寄存器控制器不返回错误

Question

我在使用Symfony应用程序中的FOSUB来管理我的用户。我过度使用了寄存器模板和控制器来使用Ajax并定制了一些东西。如果用户继续注册而没有错误，它可以正常工作。但是如果有什么不对劲的话。$form->isValid()返回false，但$form->getErrors()数组为空。经过一些研究，我仍然不知道如何检索这些错误。有人想到办法了吗？谢谢:)这是我的控制器：

public function registerAction(Request $request)
{
    if($request->isXmlHttpRequest())
    {
        $returnArray = array();
        /** @var $formFactory \FOS\UserBundle\Form\Factory\FactoryInterface */
        $formFactory = $this->container->get('fos_user.registration.form.factory');
        /** @var $userManager \FOS\UserBundle\Model\UserManagerInterface */
        $userManager = $this->container->get('fos_user.user_manager');
        /** @var $dispatcher \Symfony\Component\EventDispatcher\EventDispatcherInterface */
        $dispatcher = $this->container->get('event_dispatcher');

        $user = $userManager->createUser();
        $user->setEnabled(true);

        $event = new GetResponseUserEvent($user, $request);
        $dispatcher->dispatch(FOSUserEvents::REGISTRATION_INITIALIZE, $event);

        if (null !== $event->getResponse()) {
            return $event->getResponse();
        }

        $form = $formFactory->createForm();
        $form->setData($user);

        if ('POST' === $request->getMethod()) {
            $form->bind($request);

            if ($form->isValid()) {
                $event = new FormEvent($form, $request);
                $dispatcher->dispatch(FOSUserEvents::REGISTRATION_SUCCESS, $event);
                $userManager->updateUser($user);

                if (null === $response = $event->getResponse()) {
                    $returnArray[] = array("success" => "Registration confirmed.");
                    $returnArray[] = array("info" => "An email has been send.");
                }

                    $dispatcher->dispatch(FOSUserEvents::REGISTRATION_COMPLETED, new FilterUserResponseEvent($user, $request, $response));

                return new Response(json_encode($returnArray));
            }
            else
            {
                foreach($form->getErrors() as $error)
                    $returnArray[] = array("error" => $error->getMessage());

                return new Response(json_encode($returnArray));
            }
        }
    }
    return new Response("This is not XHR");
}

Answer 1

要显示密码字段的错误，必须在密码字段上显示错误。{ form_errors(form.plainPassword.first) }.如果只执行{{ form_errors(form.plainPassword) }}，则错误不会返回，因为错误不会冒泡。