根据键的值将散列数组拆分为两部分

Question

如何根据ate键的值将这个哈希数组分割成两个？

array = [
  { name: "Gad", ate: true },
  { name: "Lad", ate: false },
  { name: "Bad", ate: true },
  { name: "Sad", ate: false }
]

示例输出

array_1 = [
  { name: "Gad", ate: true },
  { name: "Bad", ate: true }
]
array_2 = [
  { name: "Lad", ate: false },
  { name: "Sad", ate: false }
]

Answer 1

使用Enumerable#partition方法：

array.partition { |x| x[:ate] }
# => [[{:name=>"Gad", :ate=>true}, {:name=>"Bad", :ate=>true}], 
#     [{:name=>"Lad", :ate=>false}, {:name=>"Sad", :ate=>false}]]

或者：

array_1, array_2 = array.partition { |x| x[:ate] }

array_1
# => [{:name=>"Gad", :ate=>true}, {:name=>"Bad", :ate=>true}]

array_2
# => [{:name=>"Lad", :ate=>false}, {:name=>"Sad", :ate=>false}]

Answer 2

array_one, array_two = *array.group_by { |x| x[:ate] }.map(&:last)

=> array_one
=> # [{:name=>"Gad", :ate=>true}, {:name=>"Bad", :ate=>true}]
=> array_two
=> # [{:name=>"Lad", :ate=>false}, {:name=>"Sad", :ate=>false}]

thx @CarySwoveland

Answer 3

我无法与partition竞争，但另一种方式是：

trues  = array.select { |h| h[:ate] }
falses = array - trues