由于某些原因,我的代码没有更新mySQL数据库,但它没有报告任何错误。
register.php (表格)
<form class="register_form" action="action.php?do=register" method="post">
Team Name*: <input type="text" name="teamname" required />
Team Region*: <input type="text" name="teamregion" maxlength="4" required />
Team Leader*: <input type="text" name="teamleader" maxlength="16" required />
Team Members: <input type="text" name="teammembers" />
<input name="register_submit" type="submit" value="Register" />
</form>action.php
<?php
$con=mysqli_connect("192.185.#.###","########_reg","#######","#########");
if (mysqli_connect_errno()) {echo "Failed to connect to MySQL: " . mysqli_connect_error();}
$action = $_GET['do'];
if($action=="register") {
$teamname = $_POST["teamname"];
$teamregion = $_POST["teamregion"];
$teamleader = $_POST["teamleader"];
$teammembers = $_POST["teammembers"];
$result = mysqli_query($con, "INSERT INTO teams (teamname, region, teamleader, teammembers, wins, loses)
VALUES (" . $teamname . "," . $teamregion . "," . $teamleader . "," . $teammembers . ",0,0);");
}
?>知道为什么不能正常工作吗?
发布于 2014-01-26 17:54:14
下面是一个带有准备好的语句的工作示例,这些语句“更好”用于一般而不是query
action.php
$con = new mysqli('localhost', 'root', '', 'dachi');
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
if (isset($_GET['do']) && $_GET['do'] === "register") {
$teamname = $_POST["teamname"];
$teamregion = $_POST["teamregion"];
$teamleader = $_POST["teamleader"];
$teammembers = $_POST["teammembers"];
$wins = 0;
$loses = 0;
$stmt = $con->prepare("INSERT INTO `teams` (`teamname`,`region`,`teamleader`,`teammembers`,`wins`,`loses`) VALUES (?,?,?,?,?,?)");
$stmt->bind_param('ssssii', $teamname, $teamregion, $teamleader, $teammembers, $wins, $loses);
$stmt->execute();
$stmt->close();
}register.php
<form class="register_form" action="action.php?do=register" method="post">
Team Name*: <input type="text" name="teamname" required />
Team Region*: <input type="text" name="teamregion" maxlength="4" required />
Team Leader*: <input type="text" name="teamleader" maxlength="16" required />
Team Members: <input type="text" name="teammembers" />
<input name="register_submit" type="submit" value="Register" />
</form>发布于 2014-01-26 17:50:47
你应该改变:
if($action=="register") {至
if($action=="register_submit") {因为输入的标记名设置为值register_submit,而不是注册。
并将$action = $_GET['do'];更改为$action = $_POST['register_submit'];
https://stackoverflow.com/questions/21366970
复制相似问题