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社区首页 >问答首页 >Awesomium中局部含量的加载

Awesomium中局部含量的加载
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Stack Overflow用户
提问于 2014-01-24 15:29:38
回答 2查看 2.2K关注 0票数 1

我编写了一个本地DataSource,因为据我所知,Awesomium中没有包含任何内容,但问题是它请求数据源html、图像等中的所有内容,而且我也不知道如何加载所有类型的mime格式。我的当前代码只支持html/text,其中我将文件加载到二进制文件中并作为响应发送。这不适用于图像。

有人知道我该从这里走到哪里吗?

代码语言:javascript
复制
class LocalDataSource : 
    public Awesomium::DataSource
{
public:
    LocalDataSource() { }
    virtual ~LocalDataSource() { }

    virtual void OnRequest(int request_id, const Awesomium::WebString& path)
    {
        std::string filepath = Awesomium::ToString(path).insert(0, "./");
        std::basic_ifstream<char> is(filepath, std::ios_base::in | std::ios_base::binary);
        if (is)
        {
            is.seekg(0, is.end);
            int length = is.tellg();
            is.seekg(0, is.beg);

            char *buffer = new char[length + 1];
            is.read(buffer, length);
            buffer[length] = '\0';
            is.close();

            SendResponse(request_id, strlen(buffer), (unsigned char*)buffer, Awesomium::WSLit("text/html"));
            delete[] buffer;
        }
        else
        {
            // Error 
        }
    }
};

编辑:

现在,我将相对于可执行文件加载文件,而不是使用DataSource的文件。

EN

回答 2

Stack Overflow用户

回答已采纳

发布于 2014-07-25 07:16:44

我知道这是很古老的,但它与我相关,我用与Steven相同的方式修复了它,我将发布我使用的C++代码:

代码语言:javascript
复制
bool ResInterceptor::OnFilterNavigation(int origin_process, int origin_routing_id, const Awesomium::WebString& method, const Awesomium::WebURL& url, bool is_main_frame) 
{
    return false;
}

Awesomium::ResourceResponse* ResInterceptor::OnRequest(Awesomium::ResourceRequest* request)
{
    bool isAsset = std::strcmp(ToString(request->url().scheme()).c_str(), "asset")==0;
    bool isFile = std::strcmp(ToString(request->url().scheme()).c_str(), "file")==0;

    if(!isAsset && !isFile)
    {
        //if it is neither of these we "may" still intercept the call, this allows for offline-online versions to work
        return Awesomium::ResourceInterceptor::OnRequest(request);
    }

    if(isAsset)
    {
        //Blah blah, do whatever
    }
    else if(isFile)
    {
        //Blah blah, same
    }

    //As you can see this isn't very, but it worked for my purposes
    std::string contentpath = "E:/Location/of/files" + ToString(request->url().path()); 

    Awesomium::WebString datatype;
    std::string filename = Awesomium::ToString(request->url().filename());

    //I still want to check for the correct mime type
    if     (has_suffix(filename, ".html")) datatype = Awesomium::WSLit("text/html");
    else if(has_suffix(filename, ".js"))   datatype = Awesomium::WSLit("text/javascript");
    else if(has_suffix(filename, ".css"))  datatype = Awesomium::WSLit("text/css");
    else if(has_suffix(filename, ".swf"))  datatype = Awesomium::WSLit("application/x-shockwave-flash");
    else if(has_suffix(filename, ".zip"))  datatype = Awesomium::WSLit("application/zip");
    else if(has_suffix(filename, ".txt"))  datatype = Awesomium::WSLit("text/plain");
    else if(has_suffix(filename, ".text")) datatype = Awesomium::WSLit("text/plain");
    else if(has_suffix(filename, ".png"))  datatype = Awesomium::WSLit("image/png");
    else if(has_suffix(filename, ".jpeg")) datatype = Awesomium::WSLit("image/jpeg");
    else if(has_suffix(filename, ".jpg"))  datatype = Awesomium::WSLit("image/jpeg");
    else if(has_suffix(filename, ".webm")) datatype = Awesomium::WSLit("video/webm");
    else if(has_suffix(filename, ".mp4"))  datatype = Awesomium::WSLit("video/mp4");
    else if(has_suffix(filename, ".ogv"))  datatype = Awesomium::WSLit("video/ogg");
    else if(has_suffix(filename, ".flv"))  datatype = Awesomium::WSLit("video/flv");

    if(!datatype.IsEmpty())
    {
        FILE * pFile;
        long lSize;
        unsigned char * buffer;
        size_t result;

        pFile = fopen ( contentpath.c_str() , "rb" );
        if (pFile!=NULL)
        {
            // obtain file size:
            fseek (pFile , 0 , SEEK_END);
            lSize = ftell (pFile);
            rewind (pFile);

            // allocate memory to contain the whole file:
            buffer = (unsigned char*) malloc (sizeof(unsigned char)*lSize);
            if (buffer == NULL) {fputs ("Memory error",stderr); exit (2);}

            // copy the file into the buffer:
            result = fread (buffer,1,lSize,pFile);
            if (result != lSize) {fputs ("Reading error",stderr); exit (3);}

            //This is where the magic happens!!
            return Awesomium::ResourceResponse::Create(lSize, buffer, datatype);

            // terminate
            fclose (pFile);
            free (buffer);
        }
        else
        {
            //send this off to the default request handler instead of it being a local file
            return Awesomium::ResourceInterceptor::OnRequest(request);
        }
    }else
    {
        //send this off to the default request handler instead of it being a local file
        return Awesomium::ResourceInterceptor::OnRequest(request);
    }
}

//Support function
bool ResInterceptor::has_suffix(const std::string &str, const std::string &suffix)
{
    return str.size() >= suffix.size() &&
           str.compare(str.size() - suffix.size(), suffix.size(), suffix) == 0;
}

至于我是如何将它连接起来的,我只是添加了这一行代码:

代码语言:javascript
复制
_web_core = WebCore::Initialize(config);
_web_core->set_resource_interceptor(new ResInterceptor());

这花了我整整一个晚上的时间,因为我是用一个变量传入一个指针,而不是直接使用"new“关键字!至少我现在拿到了!

还请注意,我在LocalDataSource中尝试了完全相同的代码,除了文本文件之外,它没有工作,所以我认为里面有一个bug,好消息是,这是完全相同的工作方式,但是您可以更好地控制每个文件请求。

谢谢你,史蒂文的所有伟大的参考代码!

票数 1
EN

Stack Overflow用户

发布于 2014-02-02 15:18:15

简单的方法是发送文件的内容而不需要出汗,mime类型检测是使用静态方法static ResourceResponse* Awesomium::ResourceResponse::Create

来自Awesomium文档

从磁盘上的文件创建ResourceResponse。

我想不出如何将ResourceResponse::Create映射到DataSource::SendResponse

作为解决办法,您可以将数据源重写为IResourceInterceptor而不是DataSource。我用C#在如何为嵌入式资源使用http:// http而不是自定义资产://http上编写了一个详细的示例,将C#转换为C++应该非常简单。下面是我的文章的编辑版本(没有测试)。

代码语言:javascript
复制
using System;
using System.IO;
using System.Reflection;
using Awesomium.Core;

namespace MyApp
{
    public class ResourceInterceptor : IResourceInterceptor
    {
        /// <summary>
        ///     Intercepts any requests for the EmbeddedResourceDomain base Uri,
        ///     and returns a response using the embedded resource in this app's assembly/DLL file
        /// </summary>
        public virtual ResourceResponse OnRequest(ResourceRequest request)
        {
            ResourceResponse response = null;
            string resourceName;
            string filePath;

            filePath = String.Concat("./", request.Url.AbsolutePath);
            filePath = Path.GetFullPath(resourceName.Replace('/', Path.DirectorySeparatorChar));

            // cache the resource to a temp file if 
            if (File.Exists(filePath))
            {
                response = ResourceResponse.Create(filePath);
            }

            return response;
        }

        /// <summary>
        ///     Optionally blocks any web browser requests by returning true.  Not used.
        /// </summary>
        /// <remarks>
        ///     This method can implement a whitelist of allowed URLs here by
        ///     returning true to block any whitelist misses
        /// </remarks>
        public virtual bool OnFilterNavigation(NavigationRequest request)
        {
            return false;
        }
    }
}

另一种选择可能是对HTML内容进行黑客攻击,在文档的<base href="file:///c:/my/bin/path" />中注入一个<head>元素。在加载内容之前,需要修改href属性值。这可能比它的价值更多的工作。

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/21336391

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