继续获取python中的语法错误

Question

我正在做麻省理工学院开放课件课程6.00计算机科学和编程入门课程，我被塞进了第8期作业的第2题，我应该创建一个贪婪的算法，根据价值和工作关系，给学生尽可能最好的科目。

这是我的代码中的一部分，在代码中，我得到了语法错误，并且似乎找不出出了什么问题：

subjects={'6.00':   (16,   8),'1.00':   (7,    7),'6.01':   (5,    3), '15.01':  (9,    6)}


def greedyAdvisor(subjects, maxWork, comparator):
    """
    Returns a dictionary mapping subject name to (value, work) which includes
    subjects selected by the algorithm, such that the total work of subjects in
    the dictionary is not greater than maxWork.  The subjects are chosen using
    a greedy algorithm.  The subjects dictionary should not be mutated.

    subjects: dictionary mapping subject name to (value, work)
    maxWork: int >= 0
    comparator: function taking two tuples and returning a bool
    returns: dictionary mapping subject name to (value, work)
    """

    bestSubjects={}
    currentWork=0
    NA=['0']
    while currentWork<maxWork:
        candidate=find_best_sub(subjects,comparator)
        candidate_work= find_work(candidate)
        if candidate_work+currentWork<=15:
          d2={candidate:subjects[candidate]
          NA.append(candidate)
          bestSubjects.update(d2)
          currentWork+=candidate_work
        elif candidate_work+currentWork>15:
              continue
      return bestSubjects




def find_best_sub(subjects,comparator, NA):
    """returns the best subject according to a comparator, the subject must be available so if it's in the NA list it wont be considered"""
  subs= subjects.keys()
  subs=list(subs)
  best_subject='1.00'
  for subject in subs:
    if subject not in NA:
        if comparator(subjects[subject],subjects[best_subject])== True:
          best_subject= subject
        elif comparator(subjects[subject],subjects[best_subject])== False:
          continue
  return best_subject

def find_work(subjects,sub):
  work=sub[WORK]
  return work

Answer 1

正如经常发生的那样，错误线高于所报告的一行：

      d2={candidate:subjects[candidate]
      NA.append(candidate)

在本例中，您没有关闭d2声明中的大括号

      d2={candidate:subjects[candidate]} #<--- here
      NA.append(candidate)

Answer 2

          d2={candidate:subjects[candidate]
          NA.append(candidate)

你掉了个支架。

下一次，查看错误消息：

    NA.append(candidate)
     ^
SyntaxError: invalid syntax

然后看看它指向的那条线和上面的那条线。