首页
学习
活动
专区
圈层
工具
发布
社区首页 >问答首页 >aSmack - MultiUserChat.getJoinedRooms返回空迭代器

aSmack - MultiUserChat.getJoinedRooms返回空迭代器
EN

Stack Overflow用户
提问于 2014-01-21 07:25:38
回答 1查看 1.7K关注 0票数 0

我正在开发一个安卓应用程序,它利用ASmack向后台服务中的服务器发送XMPP消息。我可以通过调用MultiUserChat加入MultiUserChat.join(connection.getUser());。我可以通过调用MultiUserChat.isJoined();来确认我加入了聊天,它返回true。而且,由于我使用的是www.hosted.im,我可以看到我在会议室使用他们的在线UI。在另一个函数中,我尝试使用MultiUserChat.getJoinedRooms(connection, connection.getUser());检索连接的房间列表,但是返回一个空的迭代器。

代码语言:javascript
复制
private XMPPConnection connection;

/*... Connect to server and login with username and password ...*/

public Iterator<String> getJoinedRooms() {
    Log.i(ChatListActivity.TAG, "Trying to get joined rooms");
    Iterator<String> result = null;
    if(connection != null) {
        Log.i(ChatListActivity.TAG, "Returning joined chat rooms as " + connection.getUser());
        result = MultiUserChat.getJoinedRooms(connection, connection.getUser());
        while(result.hasNext()) {
           Log.w(ChatListActivity.TAG, result.next());
        }
    } else {
        Log.e(ChatListActivity.TAG, "Cannot get joined rooms.  Connection == NULL");
    }

    if(result == null || (result != null && !result.hasNext())) {
        ArrayList<String> resultArr = new ArrayList<String>();
        resultArr.add(getString(R.string.no_chat_rooms_joined));
        result = resultArr.iterator();
        Log.i(ChatListActivity.TAG, "Returning EMPTY ITERATOR for joined chat rooms");
    }
    return result;
}

public void joinRoom(String room) {
    if(connection != null) {
        Log.i(ChatListActivity.TAG, "Joining room " + room);
        // Create a MultiUserChat using a Connection for a room
        MultiUserChat muc2 = new MultiUserChat(connection, "testroom@conference.konstadtest.p1.im");

        try {
            muc2.join(connection.getUser());
            muc2.grantVoice(connection.getUser());
            muc2.grantMembership(connection.getUser());
            if(muc2.isJoined())
                Log.w(ChatListActivity.TAG, "Joined room " + room + " as " + connection.getUser());
            else
                Log.w(ChatListActivity.TAG, "Failed to join " + room + " as " + connection.getUser());
        } catch (XMPPException e) {
            e.printStackTrace();
            Log.w(ChatListActivity.TAG, "Cannot join room " + room);
        }
    } else {
        Log.w(ChatListActivity.TAG, "Cannot join room " + room + " because connection is NULL");
    }
}

我做错了什么?我打电话给SmackAndroid.init(getApplicationContext());,然后再打电话给其他人。

谢谢你的帮助,

克里斯

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2014-03-08 09:20:51

我所做的是,在被加入的房间后,我添加了一个包侦听器。我还得到了一个空列表,但是在调试时,我检查服务器发送的结果xml记录中是否返回了这些房间,因此我手动添加了ha数据包侦听器,如下所示:

代码语言:javascript
复制
public void AddPacketListener(){
    PacketFilter filter = new IQTypeFilter(IQ.Type.RESULT);
    MyService.getConnection().addPacketListener(new PacketListener() 
    {   
    public void processPacket(Packet paramPacket) {

    if(paramPacket.getFrom().equals(MyService.getConnection().getUser())){
            String xml=paramPacket.toXML();
            String from[];

            System.out.println(xml);
            from=paramPacket.getFrom().split("/");
                Pattern pattern = Pattern.compile("<item jid=\"(.*?)/>");
                Matcher matcher = pattern.matcher(xml);
                String parts[];

                Roomlist.clear();
                while (matcher.find()) {    

                    parts=matcher.group(1).split("@");
                    Roomlist.add(parts[0]);

                }      
                return;         
                }

    }
    },filter);

}
票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/21251761

复制
相关文章

相似问题

领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档