将DCOM转换为JPG

Question

我需要将DCOM映像转换成JPG映像，我使用的是来自本站的本站。但我无法将转换后的图像保存在我的var_dump()中。答复如下：

object(dicom_convert)#1 (5) {
    ["file"] => string(62) "img/dcom/1.2.826.0.1.3680043.2.634.0.12779.2012316.9235.11.dcm"
    ["jpg_file"] => string(66) "img/dcom/1.2.826.0.1.3680043.2.634.0.12779.2012316.9235.11.dcm.jpg"
    ["tn_file"] => string(69) "img/dcom/1.2.826.0.1.3680043.2.634.0.12779.2012316.9235.11.dcm_tn.jpg"
    ["jpg_quality"] => int(100)
    ["tn_size"] => int(125)
}

因此，据我所知，在jpg_file中，我保存了(？)JPG图像，还是不？如果没有，我怎样才能拯救它呢？

因为如果我用

$jpg = imagecreatefromjpeg('http://localhost/'.$d->jpg_file);
imagejpeg($jpg, NULL);`

我犯了个错误

Warning: imagecreatefromjpeg(http://localhost/img/dcom/1.2.826.0.1.3680043.2.634.0.12779.2012316.9235.11.dcm.jpg) [function.imagecreatefromjpeg]: failed to open stream: HTTP request failed! HTTP/1.1 404 Not Found in O:\home\localhost\www\dcm_to_jpg.php on line 29

Warning: imagejpeg(): supplied argument is not a valid Image resource in O:\home\snimki\www\dcm_to_jpg.php on line 30

有人能停下来回答我的问题吗？

UPD1:

好的，正如我所看到的，我无法保存转换的图像，所以我无法访问不存在的文件.所以我有第二个问题，谁能帮我保存我从class_dicom.php类得到的转换成的JPG图片.我只是找不到保存文件的功能.

Answer 1

试试这个吧。

header("Content-type: image/jpeg");

echo file_get_contents($imgPath); //$imgPath -> img/dcom/1.2.826.0.1.3680043.2.634.0.12779.2012316.9235.11.dcm_tn.jpg