来自AudioRecord的振幅

Question

我有一些代码，应该是从AudioRecord中得到振幅。问题是数学只返回-Infinity。我能再多看一看吗？

private class measureSnoreAudio extends AsyncTask<String, String, String> {

    @Override
    protected String doInBackground(String... params) {


            Log.d(TAG, "Creating the buffer of size " + BUFFER_SIZE);
            byte[] buffer = new byte[BUFFER_SIZE];

            Log.d(TAG, "Creating the AudioRecord");
            recorder = new AudioRecord(MediaRecorder.AudioSource.MIC,
                    RECORDING_RATE, CHANNEL, FORMAT, BUFFER_SIZE * 10);

            Log.d(TAG, "AudioRecord recording...");
            recorder.startRecording();

            while (isRecordingSnore) {

                // read the data into the buffer
                int read = recorder.read(buffer, 0, buffer.length);
                int amplitude = (buffer[0] & 0xff) << 8 | buffer[1];

                // Determine amplitude
                double amplitudeDb = 20 * Math
                        .log10(Math.abs(amplitude) / 32768);
                String dbString = String.valueOf(amplitudeDb);
                Log.d("Snore DB", "dB " + dbString);
                //TextView textAmplitude = (TextView) findViewById(R.id.tvAmplitude);
                //textAmplitude.setText(dbString);
            }

            Log.d(TAG, "AudioRecord finished recording");
        return null;
    }
}

Answer 1

double amplitudeDb = 20 * Math.log10(Math.abs(amplitude) / 32768);

我认为问题可能来自于Math.abs(振幅) / 32768，振幅是整数，所以Math.abs(振幅)也会返回整数，因为Math.abs(振幅)小于32768 (也许我不正确，字节是最大值2^7-1，这里的振幅可以大于32768？)。所以Math.abs(振幅)/ 32768等于0。Log10(0)是-Infinity，我在中进行了测试。你可以换到

double amplitudeDb = 20 * Math.log10((double)Math.abs(amplitude) / 32768);