对于春季社交facebook图书馆的实现,我会非常感激。我正在尝试执行FQL查询,但是facebook给我发送了空的结果。如果我在中执行相同的查询,它的工作原理就像一个魅力。我检查了所有权限。我的代码是这样的:
private static final String FQL_GET_FRIENDS = "SELECT uid, name FROM user WHERE uid IN(SELECT uid2 FROM friend WHERE uid1 = me())";
Facebook facebook = new FacebookTemplate(token);
List<Reference> references = facebook.userOperations().search(FQL_GET_FRIENDS);谢谢你的建议
发布于 2014-01-09 09:17:05
好的。这对我起了作用:
MultiValueMap<String, String> parameters = new LinkedMultiValueMap<String, String>();
parameters.set("q", FQL_GET_FRIENDS);
Map<String, Object> resultSet = (Map<String, Object>) facebookTemplate
.fetchObject("fql", Map.class, parameters);发布于 2014-01-07 12:54:46
我通过简单的HTTP请求使用具有足够权限的有效令牌对"faceBookURL“进行了同样的操作,您可以使用以下命令:
private static String STR_FACEBOOK_FQL_URL = "https://api.facebook.com/method/fql.query?query=";
private static String STR_FACEBOOK_RETURN_FORMAT = "&format=json";
private static String STR_FACEBOOK_ENCODE_FORMAT = "UTF-8";
private static String STR_FACEBOOK_ACCESS_TOKEN = "&access_token=";
private static final String FQL_GET_FRIENDS = "SELECT uid, name FROM user WHERE uid IN(SELECT uid2 FROM friend WHERE uid1 = me())";
String encodedQuery = URLEncoder.encode(FQL_GET_FRIENDS, STR_FACEBOOK_ENCODE_FORMAT);
String faceBookURL = STR_FACEBOOK_FQL_URL + encodedQuery + STR_FACEBOOK_RETURN_FORMAT
+ STR_FACEBOOK_ACCESS_TOKEN + token;https://stackoverflow.com/questions/20968402
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