如果给定日期(例如-“2014-01-07”),我希望访问该特定月份(2014年1月),并获取该月份的date number of the Sundays和Sunday。
在这种情况下,4,11,18,25 -星期六5,12,19,26 -星期日
我想使用java脚本,因为这是一个前端开发。帮我解决this..Thnkz问题
发布于 2014-01-03 07:39:16
尝试使用这个小提琴
var d = new Date();
var getTot = daysInMonth(d.getMonth(),d.getFullYear()); //Get total days in a month
var sat = new Array(); //Declaring array for inserting Saturdays
var sun = new Array(); //Declaring array for inserting Sundays
for(var i=1;i<=getTot;i++){ //looping through days in month
var newDate = new Date(d.getFullYear(),d.getMonth(),i)
if(newDate.getDay()==0){ //if Sunday
sun.push(i);
}
if(newDate.getDay()==6){ //if Saturday
sat.push(i);
}
}
console.log(sat);
console.log(sun);
function daysInMonth(month,year) {
return new Date(year, month, 0).getDate();
}在sat和sun Array()中,您可以得到特定月份的星期六和星期日。
发布于 2014-01-03 07:27:36
使用getDate方法非常容易:
var my_date = "2014-01-07".split('-')
var year = parseInt(my_date[0]);
var month = parseInt(my_date[1])-1;
var saturdays = [];
var sundays = [];
for (var i = 0; i <= new Date(year, month, 0).getDate(); i++)
{
var date = new Date(year, month, i);
if (date.getDay() == 6)
{
saturdays.push(date);
}
else if (date.getDay() == 0)
{
sundays.push(date);
}
};
console.log(sundays, saturdays);发布于 2014-01-03 07:44:00
var d = new Date();
var pred = new Date(d.getFullYear(),d.getMonth()+1,0).getDate();
var nowd;
var sat_array = "";
var sun_array = "";
for (i=1;i<=pred;i++) {
try {
console.log(d.getFullYear()+ "-" + (d.getMonth()+1) + "-" + i);
nowd = new Date(d.getFullYear()+ "-" + (d.getMonth()+1) + "-" + i)
if (nowd.getUTCDay() == 5)
{
sat_array = sat_array + "," + i;
}
if (nowd.getUTCDay() == 6)
{
sun_array = sun_array + "," + i;
}
}
catch(e) {
return;
}
}
console.log("SAT list : " +sat_array);
console.log("SUN list : " +sun_array);https://stackoverflow.com/questions/20898661
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