我用tableGrob生成了一个20Cx10R表,发现它非常慢。因此,我试图找出原因。巴普蒂斯特自己在Has anyone else noticed that tableGrob is slow?中提到了原因。
我尝试了他的例子:http://rpubs.com/baptiste/ftableGrob。初始运行良好,即他的示例中的表生成得非常快。
但是,当我试图加载grid.draw(g) gridExtra以添加ggplot中的绘图时,Error in as.matrix(d) : object 'd' not found 生成了以下错误:Error in as.matrix(d) : object 'd' not found
我的代码在这里(稍微修改了巴普蒂斯特的原始代码):
library(grid)
library(gridExtra) # NOTE: Loading gridExtra clashes w grid.draw(g) later
aa <- head(iris, 10)
padding = unit(4, "mm")
nc <- ncol(aa)
nr <- nrow(aa)
extended_matrix <- cbind(c("", rownames(aa)), rbind(colnames(aa), as.matrix(aa)))
w <- apply(extended_matrix, 2, strwidth, "inch")
h <- apply(extended_matrix, 2, strheight, "inch")
widths <- apply(w, 2, max)
heights <- apply(h, 1, max)
padding <- convertUnit(padding, unitTo = "in", valueOnly = TRUE)
x <- cumsum(widths + padding) - 0.5 * padding
y <- cumsum(heights + padding) - padding
rg <- rectGrob( x = unit(x - widths/2, "in"), y = unit(1, "npc") -
unit(rep(y, each = nc + 1), "in"),
width = unit(widths + padding, "in"),
height = unit(heights + padding, "in") )
tg <- textGrob( c(t(extended_matrix)), x = unit(x - widths/2, "in"),
y = unit(1, "npc") - unit(rep(y, each = nc + 1), "in"),
just = "center" )
g <- gTree( children = gList(rg, tg), x = x, y = y, widths = widths,
heights = heights, cl = "table",
gp=gpar(fill = rep(c("grey90", "grey95"), each = 2)))
l <- linesGrob()
grid.draw(l) # Added to show that grid.draw works here...
grid.draw(g) # ... but not here *confused*
invisible(g)
grid.arrange( g, g, ncol=2) # I eventually hope to use ggplot2 w the tables drawn with grid.draw
## End of code ##我对此进行了研究,但没有发现类似的报告/帖子。我怀疑这是因为我对gridExtra的理解很差,所以我提出这件事是为了寻求‘启示’。如果有人能帮忙就好了!
旁白:由于巴普蒂斯特的原始代码也使用“d”,在将“d”转换为“aa”后,R仍然高喊“对象'd‘not!”。想象一下我的困惑!
最后,祝大家新年快乐(2014)!
发布于 2014-01-01 13:30:09
加载gridExtra时,为类“表”对象带来一个drawDetails方法(由grid.draw调用),该方法与此gTree不兼容(缺少一些属性)。为了简短起见,您应该简单地删除cl = "table"中的gTree,或者选择另一个名称。
https://stackoverflow.com/questions/20865033
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