如何在红宝石中进行base58编码？

Question

我试图用原始格式编码一个原母兔钱包地址，如比特币 wiki到Base58格式中所解释的那样。

原始兔子的地址以P (版本号56)开头。

我已经给出了交易的原始地址。看起来是这样：

028401a2e512b1b91b882ee1c9291cd407c10916bf791662f7189c9c805643e51c

现在，我已经从wiki逐步地遵循了指南，我的红宝石代码看起来是这样的：

# 1 - Take the corresponding public key generated with it (65 bytes, 1 byte 0x04, 32 bytes corresponding to X coordinate, 32 bytes corresponding to Y coordinate)
  sender = '028401a2e512b1b91b882ee1c9291cd407c10916bf791662f7189c9c805643e51c'
# 2 - Perform SHA-256 hashing on the public key 
  sender = Digest::SHA256.new.update(sender)
# 3 - Perform RIPEMD-160 hashing on the result of SHA-256
  sender = Digest::RMD160.new.update(sender.to_s)
# 4 - Add version byte in front of RIPEMD-160 hash (0x00 for Main Network) 
  sender = '00' + sender.to_s
# 5 - Perform SHA-256 hash on the extended RIPEMD-160 result 
  checksum = Digest::SHA256.new.update(sender.to_s)
# 6 - Perform SHA-256 hash on the result of the previous SHA-256 hash 
  checksum = Digest::SHA256.new.update(checksum.to_s)
# 7 - Take the first 4 bytes of the second SHA-256 hash. This is the address checksum 
  checksum = checksum.to_s[0,8]
# 8 - Add the 4 checksum bytes from point 7 at the end of extended RIPEMD-160 hash from point 4. This is the 25-byte binary Bitcoin Address. 
  sender += checksum

到目前为止，这似乎效果很好。我目前的结果如下：

0073eb40b21b02c08e93f6ef1bec5828763ac89e456c2f6fec

但现在我被困住了。我正在使用杜格尔的base58宝石并试图最终对地址进行编码：

# 9 - Convert the result from a byte string into a base58 string using Base58Check encoding. This is the most commonly used Bitcoin Address format 
  sender = Base58.encode(sender)

但我得到了以下问题：

/path/to/base58.rb:23:in `int_to_base58': Value passed is not an Integer. (ArgumentError)

当然不是整数。我是不是搞砸了这里的数据类型？该怎么做才能让这件事正常运作？

谢谢!

Answer 1

在我看来，就像一个十六进制数字卡在一个字符串中，让它成为一个数字：

2.0.0p247 :001 > require 'base58'
 => true 
2.0.0p247 :002 > x = '0073eb40b21b02c08e93f6ef1bec5828763ac89e456c2f6fec'
 => "0073eb40b21b02c08e93f6ef1bec5828763ac89e456c2f6fec" 
2.0.0p247 :003 > Base58.encode(x.to_i(16))
 => "byVwGWzMZZ7HwsufSQx6T2pRapGZWdkAL" 

不确定你的预期输出是什么，但这会执行.