厄温,我的错误与正确的例子和数据。如有需要,请在下面找到更新的查询和所有数据。我们有主表,其中包含资产ID之间的所有关系,如下所示。资产层次结构是S1,它有F11、F12、F13,而F11则有D111、D112、D113,同样F12有D121、D122、D123等。
母版表和插入脚本
请参阅链接木琴
CREATE TABLE tbl2 (c_id text ,d_id text, f_id text, s_id text);
INSERT INTO tbl2 values('100000019403','D111','F11','S1');
INSERT INTO tbl2 values('100000019404','D112','F11','S1');
INSERT INTO tbl2 values('100000019405','D113','F11','S1');
INSERT INTO tbl2 values('100000019406','D111','F11','S1');
INSERT INTO tbl2 values('100000019407','D112','F11','S1');
INSERT INTO tbl2 values('100000019408','D121','F12','S1');
INSERT INTO tbl2 values('100000019409','D122','F12','S1');
INSERT INTO tbl2 values('100000019410','D123','F12','S1');
INSERT INTO tbl2 values('100000019411','D123','F12','S1');
INSERT INTO tbl2 values('100000019412','D141','F14','S1');
INSERT INTO tbl2 values('100000019413','D131','F13','S1');
INSERT INTO tbl2 values('100000019414','D142','F14','S1');
INSERT INTO tbl2 values('100000019415','D132','F13','S1');
INSERT INTO tbl2 values('100000019416','D143','F14','S1');
INSERT INTO tbl2 values('100000019417','D133','F13','S1');
INSERT INTO tbl2 values('100000019418','D144','F14','S1');
INSERT INTO tbl2 values('100000019419','D211','F21','S2');
INSERT INTO tbl2 values('100000019420','D212','F21','S2');
INSERT INTO tbl2 values('100000019421','D213','F21','S2');
INSERT INTO tbl2 values('100000019422','D211','F21','S2');
INSERT INTO tbl2 values('100000019423','D212','F21','S2');
INSERT INTO tbl2 values('100000019424','D221','F22','S2');
INSERT INTO tbl2 values('100000019425','D222','F22','S2');
INSERT INTO tbl2 values('100000019426','D223','F22','S2');
INSERT INTO tbl2 values('100000019427','D223','F22','S2');
INSERT INTO tbl2 values('100000019428','D241','F24','S2');
INSERT INTO tbl2 values('100000019429','D231','F23','S2');
INSERT INTO tbl2 values('100000019430','D242','F24','S2');
INSERT INTO tbl2 values('100000019431','D232','F23','S2');
INSERT INTO tbl2 values('100000019432','D243','F24','S2');
INSERT INTO tbl2 values('100000019433','D233','F23','S2');
INSERT INTO tbl2 values('100000019434','D244','F24','S2');
INSERT INTO tbl2 values('100000019435','D311','F31','S3');
INSERT INTO tbl2 values('100000019436','D312','F31','S3');
INSERT INTO tbl2 values('100000019437','D313','F31','S3');
INSERT INTO tbl2 values('100000019438','D311','F31','S3');
INSERT INTO tbl2 values('100000019439','D312','F31','S3');
INSERT INTO tbl2 values('100000019440','D321','F32','S3');
INSERT INTO tbl2 values('100000019441','D322','F32','S3');
INSERT INTO tbl2 values('100000019442','D323','F32','S3');
INSERT INTO tbl2 values('100000019443','D323','F32','S3');
INSERT INTO tbl2 values('100000019444','D341','F34','S3');
INSERT INTO tbl2 values('100000019445','D331','F33','S3');
INSERT INTO tbl2 values('100000019446','D342','F34','S3');
INSERT INTO tbl2 values('100000019447','D332','F33','S3');
INSERT INTO tbl2 values('100000019448','D343','F34','S3');
INSERT INTO tbl2 values('100000019449','D333','F33','S3');
INSERT INTO tbl2 values('100000019450','D344','F34','S3');
INSERT INTO tbl2 values('100000019451','D111','F11','S1');
INSERT INTO tbl2 values('100000019452','D112','F11','S1');
INSERT INTO tbl2 values('100000019453','D113','F11','S1');
INSERT INTO tbl2 values('100000019454','D111','F11','S1');
INSERT INTO tbl2 values('100000019455','D112','F11','S1');
INSERT INTO tbl2 values('100000019456','D121','F12','S1');
INSERT INTO tbl2 values('100000019457','D122','F12','S1');
INSERT INTO tbl2 values('100000019458','D123','F12','S1');
INSERT INTO tbl2 values('100000019459','D123','F12','S1');
INSERT INTO tbl2 values('100000019460','D141','F14','S1');
INSERT INTO tbl2 values('100000019461','D131','F13','S1');
INSERT INTO tbl2 values('100000019462','D142','F14','S1');
INSERT INTO tbl2 values('100000019463','D132','F13','S1');
INSERT INTO tbl2 values('100000019464','D143','F14','S1');
INSERT INTO tbl2 values('100000019465','D133','F13','S1');
INSERT INTO tbl2 values('100000019466','D144','F14','S1');我们有带有资产ID的事务表,它只提供有关失败资产的信息。假设如果处于较高级别的资产ID失败,那么子数据也会被填充,但是在获取记录时,我们需要忽略子记录,只获取最高级别的记录。
事务数据可用3天,这将讨论三种不同的方案。场景1,对于讨论S1资产的2013-10-10年,它失败了,这也给出了需要忽略的子记录。
场景2的2013年10-11,其中谈到F21,F22,F23的失败和它的子记录。我们得忽视孩子们。注意到资产ID S1没有失败,因此不会出现在场景2的事务表中。
场景3的2013年-10-12,其中谈到F33的失败与其子女D331,D332,D333.我们只需要考虑F33,而忽略孩子。考虑D311,D312,D313,D321,D322和D323。
我们总是需要按startdatetime字段进行分组,因为父记录和子记录对于给定的条目总是具有相同的列值。
请参阅上面的链接,该链接还具有事务表和数据。
CREATE TABLE tbl1 (startdatetime text, enddatetime text, assetid text);
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'S1');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'F11');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'F12');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'F13');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'D111');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'D112');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'D113');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'D121');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'D122');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'D123');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'D131');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'D132');
INSERT INTO tbl1 values('2013-10-10 22:10:11', '2013-10-10 22:10:11', 'D133');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'F21');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'F22');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'F23');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'D211');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'D212');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'D213');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'D221');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'D222');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'D223');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'D231');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'D232');
INSERT INTO tbl1 values('2013-10-11 22:10:11', '2013-10-11 22:12:11', 'D233');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'F33');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'D311');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'D312');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'D313');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'D321');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'D322');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'D323');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'D331');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'D332');
INSERT INTO tbl1 values('2013-10-12 22:10:11', '2013-10-12 22:16:11', 'D333');预期产出:
根据事务数据表对受影响的使用者进行计数。
请帮助我对上述场景的c_id记录细节,我会得到计数。
发布于 2013-12-27 19:05:44
case1:s_id存在,然后忽略子行(F_id)和子子行(D_id)
使用CTE,解决方案可以如下所示:
WITH x AS (
SELECT d_id, f_id
FROM tbl2 t2
JOIN tbl1 t1 ON t1.assetid = t2.s_id
)
SELECT t.*
FROM tbl1 t
LEFT JOIN d ON d.d_id = t.assetid
LEFT JOIN f ON f.f_id = t.assetid
WHERE d.d_id IS NULL
AND f.f_id IS NULL解释
x标识应该忽略的d_id和f_id。d_id或f_id上匹配的行。case2:f_id存在,然后忽略父(S_id)和低(D_id)
WITH x AS (
SELECT d_id, s_id
FROM tbl2 f
JOIN tbl1 t ON t.assetid = f.f_id
)
SELECT t.*
FROM tbl1 t
LEFT JOIN x d ON d.d_id = t.assetid
LEFT JOIN x s ON s.s_id = t.assetid
WHERE d.d_id IS NULL
AND s.s_id IS NULL;-> SQLfiddle demo
case3:d_id存在,而忽略了父s_id,f_id
你明白了,不是吗?
https://stackoverflow.com/questions/20797347
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