在接下来的5个小时内随机地在一个随机的for循环中执行一项任务？

Question

如下所示，我有一个简单的循环打印4-8次。

我想让它在5个小时内随机打印4-8次.

import random

for i in range(random.randrange(4,8+1)): 
    print i+1
    print "do other stuff here..."

例如，它可以执行以下操作：

22:30: 1 do other stuff here...
22:41: 2 do other stuff here...
22:45: 3 do other stuff here...
23:50: 4 do other stuff here...
00:33: 5 do other stuff here...
01:23: 6 do other stuff here...
02:20: 7 do other stuff here...
03:10: 8 do other stuff here...

由于它是随机的，它有可能做到：

13:34: 1 do other stuff here...
13:41: 2 do other stuff here...
13:45: 3 do other stuff here...
13:50: 4 do other stuff here...

我怎么能做到这一点，我不知道如何使这两个循环一起运行。

威廉·丹曼

Sleeping for: 274 minutes
do other stuff here...
Sleeping for: 10 minutes
do other stuff here...
Sleeping for: 13 minutes
do other stuff here...
Sleeping for: 1 minutes
do other stuff here...
Sleeping for: 0 minutes
do other stuff here...
Sleeping for: 0 minutes
do other stuff here...
Sleeping for: 0 minutes
do other stuff here...
Sleeping for: 0 minutes
do other stuff here...

对于tobias_k

total = 30
timer_list = sorted(random.randint(1, total) for i in range(random.randint(4, 8)))
timer_old = 0
timer_previous = 0

print timer_list
for counter, timer in enumerate(timer_list):

    new_timer = timer_old - timer_previous
    timer_previous = timer_old
    sec = timedelta(seconds=int(new_timer))
    d = datetime(1,1,1) + sec
    if counter == 0:
        print "First is instantatious"
    else:
        if d.hour and d.minute:
            print "Sleeping for %d hour(s) %d minutes" % (d.hour, d.minute)
        elif not d.hour and d.minute:
            print "Sleeping for %d minutes and %d seconds" % (d.minute, d.second)
        else:
            print "Sleeping for %d seconds" % (d.second)
    print "done"
    time.sleep(timer - timer_old)
    timer_old = timer

Answer 1

这里有另一个变体，基于Guntram的方法(以及我自己在问题下面的评论)：

import random, time
total = 3600 * 5
times = sorted(random.randint(1, total) for i in range(random.randint(4, 8)))
last = 0
for t in times:
    time.sleep(t - last)
    last = t
    print "Do something at %02d:%02d:%02d" % (t/3600, t/60%60, t%60)

这将在5h间隔内创建4-8个时间点，并对它们进行排序。然后它会在第一段时间睡觉，做一些事情，为第一次和第二次的区别睡觉，再做一些事情，等等。

(可能的)优点是，间隔是相互独立的，应该在整个5h间隔内平均分配。在其他方法中，事件之间的间隔越来越小，因为它们是剩余时间的随机数量。

Answer 2

获取4到8之间的随机数。创建一个包含这些元素的数组。为每个元素分配0到18000之间的随机值。对数组进行排序。循环遍历数组元素。在每个循环中，睡眠数组元素中的秒数减去先前循环中已经睡眠的秒数。打印“在这里做其他事情”。重复，直到循环结束。

Answer 3

import time
import random
from time import gmtime, strftime

max_time_to_sleep = 18000
min_time_to_sleep = 120

for i in range(random.randrange(4,8+1)): 
    sleep_for = random.randrange(max_time_to_sleep)

while sleep_for < min_time_to_sleep:
   if max_time_to_sleep <= min_time_to_sleep:
       break

   sleep_for = random.randrange(max_time_to_sleep) 

if sleep_for == 0:
    sleep_for = min_time_to_sleep

time.sleep(sleep_for)

max_time_to_sleep -= sleep_for

if max_time_to_sleep < min_time_to_sleep:
    max_time_to_sleep = min_time_to_sleep

cur_time = strftime("%H:%M:%S", gmtime())

print "%s : do other stuff here..." % cur_time