我想找出一个问题。
我已经对简单的订购问题提出了疑问,但我想订购更多的细节。检查下面的链接:SQL Server : FOR XML sorting control by attribute
我举了个例子。
SQL查询
select (
select '123' AS '@id', (
select
(
select 'test' AS '@testid' , '20' AS '@order'
FOR XML path ('tree') , TYPE
),
(
select 'test2' AS '@testid' , '30' AS '@order'
FOR XML path ('tree-order') , TYPE
),
(
select 'test' AS '@testid' , '10' AS '@order'
FOR XML path ('tree') , TYPE
)
FOR XML path ('Node') , TYPE
)
FOR XML path ('Sample') , TYPE
),
(select '456' AS '@id', (
select
(
select 'test' AS '@testid' , '20' AS '@order'
FOR XML path ('tree') , TYPE
),
(
select 'test2' AS '@testid' , '30' AS '@order'
FOR XML path ('tree-order') , TYPE
),
(
select 'test' AS '@testid' , '10' AS '@order'
FOR XML path ('tree') , TYPE
)
FOR XML path ('Node') , TYPE
)
FOR XML path ('Sample') , TYPE)
FOR XML path ('Main') , TYPE结果:
<Main>
<Sample id="123">
<Node>
<tree testid="test" order="20" />
<tree-order testid="test2" order="30" />
<tree testid="test" order="10" />
</Node>
</Sample>
<Sample id="456">
<Node>
<tree testid="test" order="20" />
<tree-order testid="test2" order="30" />
<tree testid="test" order="10" />
</Node>
</Sample>
</Main>预期结果:
<Main>
<Sample id="123">
<Node>
<tree testid="test" order="10" />
<tree testid="test" order="20" />
<tree-order testid="test2" order="30" />
</Node>
</Sample>
<Sample id="456">
<Node>
<tree testid="test" order="10" />
<tree testid="test" order="20" />
<tree-order testid="test2" order="30" />
</Node>
</Sample>
</Main>最终结果:
<Main>
<Sample id="123">
<Node>
<tree testid="test" />
<tree testid="test" />
<tree-order testid="test2" />
</Node>
</Sample>
<Sample id="456">
<Node>
<tree testid="test" />
<tree testid="test" />
<tree-order testid="test2" />
</Node>
</Sample>
</Main>这是一棵一棵树的秩序。
最后,我不想在属性中显示订单信息
有人有好主意吗?
感谢所有对此感兴趣的人。
更新
谢谢大家,最后我解决了以下关于有序和移除属性问题的问题:
declare @resultData xml = (select @data.query('
element Main {
for $s in Main/Sample
return element Sample {
$s/@*,
for $n in $s/Node
return element Node {
for $i in $n/*
order by $i/@order
return $i
}
}
}'));
SET @resultData.modify('delete (Main/Sample/Node/tree/@order)');
SET @resultData.modify('delete (Main/Sample/Node/tree-order/@order)');
select @resultData发布于 2013-12-18 17:03:29
select @data.query('
element Main {
for $s in Main/Sample
return element Sample {
$s/@*,
for $n in $s/Node
return element Node {
for $i in Node/*
order by $i/@order
return
if ($i/self::tree)
then element tree { $i/@testid }
else element tree-order { $i/@testid }
}
}
}
}')发布于 2013-12-18 20:07:53
我感兴趣的是,在您的original post中,您是作为一个SQL查询的结果来生成XML的。如果是我的话,我会控制那个级别的订单。
https://stackoverflow.com/questions/20663908
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