使用PHP从另一个网站获取描述

Question

我试图在一个使用preg_match的网站上获取这个描述，只是有问题：

这是我想要得到的东西。就在<b>Game Description:</b><br />和<b>Tool v3.1 Info:之后的文本

<b>Game Description:</b><br />
Steel Diver is a new action-packed submarine combat game from Nintendo that<br />
immerses players in the 3D action with unique game controls and lush 3D<br />
environments. The player can choose from three different submarines, each<br />
with touch-screen control panels that players will have to master to guide<br />
them through treacherous undersea caverns while engaging enemy submarines,<br />
dodging depth charges and battling massive sea creatures. Steel Diver also<br />
takes advantage of the built-in gyroscope of the Nintendo 3DS system. The<br />
combination of 3D game play and one-of-a-kind controls makes for an immersive<br />
combination that must be experienced to be believed.<br />
<br />
<b>Tool v3.1 Info:

这里是我尝试过的：

    $pattern1 = '#<b>Game Description:</b><br />\s*(.*?)\s*<b>Tool v3.1 Info:#';
    preg_match($pattern1,$downloadPage,$description);
    print_r($description);

$downloadPage只是用curl打开网址，我得到了一些其他的数据，只是需要帮助这个部分。

谢谢

Answer 1

您需要 modifier在多行上进行匹配：

$pattern1 = '#<b>Game Description:</b><br />\s*(.*?)\s*<b>Tool v3.1 Info:#s';

Demo.