在Ruby中创建列表的更有效方法

Question

只是在一副牌里和2-9一起工作。

在Ruby中创建平台的首选和/或最有效的方法是什么？

它是我下面的东西，还是我还能/应该怎么做呢？

deck = []
suits = ["spades", "diamonds", "clubs", "hearts"]

for x in suits
  for y in 2..9
    w = y.to_s
    deck.push(w+" of "+x)
  end
end

Answer 1

suits = ["spades", "diamonds", "clubs", "hearts"]
deck = suits.product((2..9).to_a).map { |x,y| "#{y} of #{x}" }

如果你想要所有52张卡：

suits = ["spades", "diamonds", "clubs", "hearts"]
faces = { 1 => 'Ace', 11 => 'Jack', 12 => 'Queen', 13 => 'King' }
deck = suits.product((1..13).to_a).map { |x,y| "#{faces[y]||y} of #{x}" }
# => Ace of spades, 2 of spades, ..., King of spades, Ace of diamonds, etc.

Answer 2

我喜欢product w/ a街区

a, suits = [], ["spades", "diamonds", "clubs", "hearts"]
suits.product((2..9).to_a) {|t,n| a << "#{n} of #{t}"}

Answer 3

嗯，你可以用地图：

suits = ["spades", "diamonds", "clubs", "hearts"]
deck = suits.map { |d| (2..9).map { |x| "#{x} of #{d}" } }.flatten

但效率基本相同。