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社区首页 >问答首页 >PINV命令中的MATLAB误差

PINV命令中的MATLAB误差
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Stack Overflow用户
提问于 2013-12-11 05:35:45
回答 1查看 706关注 0票数 0

我使用的是三角剖分的曲面逼近代码,在这里复制。

代码语言:javascript
复制
[totalTris,three] = size(tri);
[totalPoints,two] = size(registeredPts);

%   1. Find the 3 equations for each vertex, and
%      place them in c_equations matrix;
% c_equations = [A for vertex 1;
%                A for vertex 2; ...
%                A for vertex totalPoints]
% c(point,row,:) gives one row from an A matrix
Btotal = zeros(3,totalPoints);
c_equations = zeros(3*totalPoints,3,9);
for pointNum = 1:totalPoints
    % B = [pixVal; x gradient; y gradient] at this vertex
    z = pixelVals(pointNum);
    B = [z; vGradientVecs(pointNum,1); vGradientVecs(pointNum,2)];

    % Compile all B matrices into a vector
    Btotal(:,pointNum) = B;

    % B = Ac
    x = registeredPts(pointNum,1);
    y = registeredPts(pointNum,2);
    A = [1   x   y   x^2  y^2  x^3     (x^2)*y  x*(y^2)  y^3; ...
         0   1   0   2*x   0   3*(x^2)  2*x*y   y^2      0; ...
         0   0   1   0    2*y  0        x^2     2*x*y    3*(y^2)];

    % Compile all A matrices into a vector
    c_equations(pointNum,1,:) = A(1,:);
    c_equations(pointNum,2,:) = A(2,:);
    c_equations(pointNum,3,:) = A(3,:);
end

%   2. Find the c values for each triangle patch
c = zeros(totalTris,9);
c9 = zeros(9,9);
for triNum = 1:totalTris
    p1 = tri(triNum,1);
    p2 = tri(triNum,2);
    p3 = tri(triNum,3);

    B9 = [Btotal(:,p1); Btotal(:,p2); Btotal(:,p3)];
    c9 = [c_equations(p1,1,:); c_equations(p1,2,:); c_equations(p1,3,:); ...
          c_equations(p2,1,:); c_equations(p2,2,:); c_equations(p2,3,:); ...
          c_equations(p3,1,:); c_equations(p3,2,:); c_equations(p3,3,:)];
    c(triNum,:) = pinv(c9)*B9;   %linsolve(c9,B9);
end

end

这是较大代码的一部分,当我运行该代码时,它在MATLAB中给出了以下错误

代码语言:javascript
复制
Error using svd
Input must be 2-D.

Error in pinv (line 29)
   [U,S,V] = svd(A,0);
Error in findBPolyCoefficients (line 50)
    c(triNum,:) = pinv(c9)*B9;

根据我的搜索,我得到了正确的pinv语法,“输入必须是2D”错误超出了我的理解,如果有人能告诉我解决这个问题的方法的话。

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回答 1

Stack Overflow用户

回答已采纳

发布于 2013-12-11 07:12:28

根据你给出的信息,它看起来c9是一个平凡的三维矩阵,即它的第二维数是1。这样的维度被称为单例维度。Squeeze是用来折叠这些维度的命令。你应该这么做,

代码语言:javascript
复制
c9=squeeze(c9); %before doing pinv

这将使c9成为一个二维矩阵,然后计算其奇异值.

票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/20511306

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