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重叠cout
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Stack Overflow用户
提问于 2013-12-05 00:24:37
回答 1查看 751关注 0票数 0

由于某种原因,第二次迭代这个循环时,cout语句会重叠。换句话说,在第一个cout之后,程序不会等待输入。我该怎么解决这个问题?

此外,在实际生活税的情况下,nPay功能是否有效?有人告诉我,税收应该乘以总额,每个人都要加起来。但是,我的方法也是一样的,特别是因为它们同时发生。

代码语言:javascript
复制
double calcGrossPay (double payRate, double hours);
double nPay (double& fedTx, double& localTx, double& stateTx, double& ssTx, double& netPay, double fPay);
void displayAll (double fPay, double netPay, string name);

double fedTx = 14, stateTx = 6, localTx = 3.5, ssTx = 4.75;

int main()
{

    while (!cin.eof())
    {
          string name;

          //cin.ignore();
          cout <<"Please enter your working name: ";
          getline (cin, name);
          !cin.eof();

          double payRate, hours;

          cout <<"Enter your pay rate and hours worked, respectively."<< endl;
          cin >> payRate >> hours;
          !cin.eof();

          double fPay = calcGrossPay (payRate, hours);

          double netPay = 0;
          netPay = nPay (fedTx, localTx, stateTx, ssTx, netPay, fPay);
          displayAll (fPay, netPay, name);

           system("pause");
    }
}


double calcGrossPay (double payRate, double hours)
{
       double extraT, fPay;
       if (hours > 40)
       {
       extraT = (hours - 40) * (1.5 * payRate);
       fPay = extraT + (40 * payRate);
       }
       else
       fPay = payRate * hours;

       return fPay;
}

double nPay (double& fedTx, double& localTx, double& stateTx, double& ssTx, double& netPay, double fPay)
{
       double totalTx = fedTx + localTx + stateTx + ssTx;
       netPay = fPay * (1 - (totalTx / 100));
       return netPay;
}

void displayAll (double fPay, double netPay, string name)
{
    cout <<"Below is "<< name << "'s salary information" << endl;

     cout << fixed << showpoint << setprecision(2) <<"\nYour calculated gross pay is $"
          << fPay << ", and your net pay is $" << netPay << endl;
}
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回答 1

Stack Overflow用户

发布于 2013-12-05 00:54:22

getline之后,流中仍有一个新行,因此您必须对其进行ignore

代码语言:javascript
复制
getline(cin, name);
cin.ignore();

另外,代替while (!cin.eof()),在检查流之前执行提取:

代码语言:javascript
复制
while (getline(cin, name))
{
    cin.ignore();
    // ...
}

这是更新的代码。我希望它对你有用:

代码语言:javascript
复制
int main()
{
    for (std::string name; (cout << "Please enter your working name: ") &&
                            getline(cin >> std::ws, name);)
    {
        if (cin.eof())
            break;

        double payRate, hours;

        cout << "\nEnter your pay rate and hours worked, respectively." << endl;

        if (!(cin >> payRate >> hours))
            break;

        double fPay = calcGrossPay(payRate, hours);

        double netPay = nPay(fedTx, localTx, stateTx, ssTx, netPay, fPay);

        displayAll(fPay, netPay, name);
        cin.get();
    }
}
票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/20389017

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