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社区首页 >问答首页 >多处理疯狂的日志记录

多处理疯狂的日志记录
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Stack Overflow用户
提问于 2013-12-02 15:54:51
回答 3查看 14.1K关注 0票数 10

我试图在多处理场景中使用python的默认日志模块。我读过:

  1. Python MultiProcess, Logging, Various Classes
  2. Logging using multiprocessing

以及关于多处理、日志记录、python类等的其他多篇文章。在阅读了这么多之后,我看到了这段代码,我无法使用python正确运行它:

代码语言:javascript
复制
import sys
import logging
from logging import INFO
from multiprocessing import Process, Queue as mpQueue
import threading
import time

from logutils.queue import QueueListener, QueueHandler


class Worker(Process):

    def __init__(self, n, q):
        super(Worker, self).__init__()
        self.n = n
        self.queue = q

        self.qh = QueueHandler(self.queue)
        self.root = logging.getLogger()
        self.root.addHandler(self.qh)
        self.root.setLevel(logging.DEBUG)        
        self.logger = logging.getLogger("W%i"%self.n)


    def run(self):
        self.logger.info("Worker %i Starting"%self.n)

        for i in xrange(10):
            self.logger.log(INFO, "testing %i"%i)

        self.logger.log(INFO, "Completed %i"%self.n)


def listener_process(queue):
    while True:
        try:
            record = queue.get()
            if record is None:
                break
            logger = logging.getLogger(record.name)
            logger.handle(record)
        except (KeyboardInterrupt, SystemExit):
            raise
        except:
            import sys, traceback
            print >> sys.stderr, 'Whoops! Problem:'
            traceback.print_exc(file=sys.stderr)

if __name__ == "__main__":

    mpq = mpQueue(-1)

    root = logging.getLogger()
    h = logging.StreamHandler()    
    f = logging.Formatter('%(asctime)s %(processName)-10s %(name)s %(levelname)-8s     %(message)s')
    h.setFormatter(f)
    root.addHandler(h)

    l = logging.getLogger("Test")
    l.setLevel(logging.DEBUG)

    listener = Process(target=listener_process,
                       args=(mpq,))
    listener.start()
    workers=[]
    for i in xrange(1):
        worker = Worker(i, mpq)
        worker.daemon = True
        worker.start()
        workers.append(worker)

    for worker in workers:
        worker.join()

    mpq.put_nowait(None)
    listener.join()

    for i in xrange(10):
        l.info("testing %i"%i)

    print "Finish"

如果执行代码,输出将以某种方式重复如下所示的行:

代码语言:javascript
复制
2013-12-02 16:44:46,002 Worker-2   W0 INFO         Worker 0 Starting
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 0
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 1
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 2
2013-12-02 16:44:46,002 Worker-2   W0 INFO         Worker 0 Starting
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 3
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 0
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 1
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 4
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 2
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 3
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 5
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 4
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 6
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 5
2013-12-02 16:44:46,004 Worker-2   W0 INFO         testing 7
2013-12-02 16:44:46,003 Worker-2   W0 INFO         testing 6
2013-12-02 16:44:46,004 Worker-2   W0 INFO         testing 8
2013-12-02 16:44:46,004 Worker-2   W0 INFO         testing 7
2013-12-02 16:44:46,004 Worker-2   W0 INFO         testing 9
2013-12-02 16:44:46,004 Worker-2   W0 INFO         testing 8
2013-12-02 16:44:46,004 Worker-2   W0 INFO         Completed 0
2013-12-02 16:44:46,004 Worker-2   W0 INFO         testing 9
2013-12-02 16:44:46,004 Worker-2   W0 INFO         Completed 0
2013-12-02 16:44:46,005 MainProcess Test INFO         testing 0
2013-12-02 16:44:46,005 MainProcess Test INFO         testing 1
2013-12-02 16:44:46,005 MainProcess Test INFO         testing 2
2013-12-02 16:44:46,005 MainProcess Test INFO         testing 3
2013-12-02 16:44:46,005 MainProcess Test INFO         testing 4
2013-12-02 16:44:46,005 MainProcess Test INFO         testing 5
2013-12-02 16:44:46,006 MainProcess Test INFO         testing 6
2013-12-02 16:44:46,006 MainProcess Test INFO         testing 7
2013-12-02 16:44:46,006 MainProcess Test INFO         testing 8
2013-12-02 16:44:46,006 MainProcess Test INFO         testing 9
Finish

在其他问题中,建议添加处理程序不止一次,但是,正如您所看到的,我只在方法中添加了一次流。我已经测试过将方法嵌入到具有相同结果的类中。

编辑:正如@max建议的(或我相信他所说的),我已经将worker类的代码修改为:

代码语言:javascript
复制
class Worker(Process):

    root = logging.getLogger()
    qh = None

    def __init__(self, n, q):
        super(Worker, self).__init__()
        self.n = n
        self.queue = q

        if not self.qh:
            Worker.qh = QueueHandler(self.queue)            
            Worker.root.addHandler(self.qh)
            Worker.root.setLevel(logging.DEBUG)

        self.logger = logging.getLogger("W%i"%self.n)

        print self.root.handlers

    def run(self):
        self.logger.info("Worker %i Starting"%self.n)

        for i in xrange(10):
            self.logger.log(INFO, "testing %i"%i)

        self.logger.log(INFO, "Completed %i"%self.n)

使用相同的结果,现在队列处理程序不再一次又一次地添加,但是仍然存在重复的日志条目,即使只有一个工作人员。

EDIT2:我对代码做了一点改动。我更改了侦听器进程,现在使用了一个QueueListener (这也是我在开始时想要的),将主代码移到一个类中。

代码语言:javascript
复制
import sys

import logging
from logging import INFO
from multiprocessing import Process, Queue as mpQueue
import threading
import time

from logutils.queue import QueueListener, QueueHandler

root = logging.getLogger()
added_qh = False

class Worker(Process):

    def __init__(self, logconf, n, qh):
        super(Worker, self).__init__()
        self.n = n
        self.logconf = logconf

#        global root
        global added_qh

        if not added_qh:
            added_qh = True
            root.addHandler(qh)
            root.setLevel(logging.DEBUG)            

        self.logger = logging.getLogger("W%i"%self.n)

        #print root.handlers

    def run(self):
        self.logger.info("Worker %i Starting"%self.n)

        for i in xrange(10):
            self.logger.log(INFO, "testing %i"%i)

        self.logger.log(INFO, "Completed %i"%self.n)


class Main(object):

    def __init__(self):
        pass

    def start(self):

        mpq = mpQueue(-1)
        qh = QueueHandler(mpq)

        h = logging.StreamHandler()

        ql = QueueListener(mpq, h)

        #h.setFormatter(f)
        root.addHandler(qh)

        l = logging.getLogger("Test")
        l.setLevel(logging.DEBUG)

        workers=[]

        for i in xrange(15):
            worker = Worker(logconf, i, qh)
            worker.daemon = True
            worker.start()
            workers.append(worker)

        for worker in workers:
            print "joining worker: {}".format(worker)
            worker.join()

        mpq.put_nowait(None)

        ql.start()

        # listener.join()

        for i in xrange(10):
            l.info("testing %i"%i)

if __name__ == "__main__":


    x = Main()
    x.start()

    time.sleep(10)

    print "Finish"

现在,主要是工作,直到我到达一定数量的工作人员(~15)时,由于某种原因,主类在do被阻塞,其余的工作人员什么也不做。

EN

回答 3

Stack Overflow用户

发布于 2016-05-12 08:08:19

我要迟到了,所以你可能不再需要答案了。问题来自这样一个事实:您已经在您的主进程中设置了一个处理程序,而在您的工作人员中您正在添加另一个处理程序。这意味着在辅助进程中,实际上有两个处理程序在管理您的数据,一个用于将日志推入队列,另一个用于写入流。

您可以简单地通过在代码中添加一个额外的行self.root.handlers = []来解决这个问题。从原始代码来看,工作人员的__init__方法如下所示:

代码语言:javascript
复制
def __init__(self, n, q):
    super(Worker, self).__init__()
    self.n = n
    self.queue = q

    self.qh = QueueHandler(self.queue)
    self.root = logging.getLogger()
    self.root.handlers = []
    self.root.addHandler(self.qh)
    self.root.setLevel(logging.DEBUG)
    self.logger = logging.getLogger("W%i"%self.n)

输出现在如下所示:

代码语言:javascript
复制
python workers.py 
2016-05-12 10:07:02,971 Worker-2   W0 INFO         Worker 0 Starting
2016-05-12 10:07:02,972 Worker-2   W0 INFO         testing 0
2016-05-12 10:07:02,973 Worker-2   W0 INFO         testing 1
2016-05-12 10:07:02,973 Worker-2   W0 INFO         testing 2
2016-05-12 10:07:02,973 Worker-2   W0 INFO         testing 3
2016-05-12 10:07:02,973 Worker-2   W0 INFO         testing 4
2016-05-12 10:07:02,973 Worker-2   W0 INFO         testing 5
2016-05-12 10:07:02,973 Worker-2   W0 INFO         testing 6
2016-05-12 10:07:02,973 Worker-2   W0 INFO         testing 7
2016-05-12 10:07:02,973 Worker-2   W0 INFO         testing 8
2016-05-12 10:07:02,973 Worker-2   W0 INFO         testing 9
2016-05-12 10:07:02,973 Worker-2   W0 INFO         Completed 0
Finish
票数 7
EN

Stack Overflow用户

发布于 2016-09-13 16:51:41

我想出了一个很简单的解决方法。它可能不健壮,而且我也不是日志模块方面的专家,但它似乎是解决我的情况的最佳解决方案。在尝试了一些代码更改(允许从multiprocess.get_logger()传入现有的记录器)之后,我不喜欢代码发生了多大的变化,并想出了一个简单易懂的简单方法(如果我一开始就这么做的话):

(工作示例,使用多处理池完成)

代码语言:javascript
复制
import logging
import multiprocessing

class FakeLogger(object):
    def __init__(self, q):
        self.q = q
    def info(self, item):
        self.q.put('INFO - {}'.format(item))
    def debug(self, item):
        self.q.put('DEBUG - {}'.format(item))
    def critical(self, item):
        self.q.put('CRITICAL - {}'.format(item))
    def warning(self, item):
        self.q.put('WARNING - {}'.format(item))

def some_other_func_that_gets_logger_and_logs(num):
    # notice the name get's discarded
    # of course you can easily add this to your FakeLogger class
    local_logger = logging.getLogger('local')
    local_logger.info('Hey I am logging this: {} and working on it to make this {}!'.format(num, num*2))
    local_logger.debug('hmm, something may need debugging here')
    return num*2

def func_to_parallelize(data_chunk):
    # unpack our args
    the_num, logger_q = data_chunk
    # since we're now in a new process, let's monkeypatch the logging module
    logging.getLogger = lambda name=None: FakeLogger(logger_q)
    # now do the actual work that happens to log stuff too
    new_num = some_other_func_that_gets_logger_and_logs(the_num)
    return (the_num, new_num)

if __name__ == '__main__':
    multiprocessing.freeze_support()
    m = multiprocessing.Manager()
    logger_q = m.Queue()
    # we have to pass our data to be parallel-processed
    # we also need to pass the Queue object so we can retrieve the logs
    parallelable_data = [(1, logger_q), (2, logger_q)]
    # set up a pool of processes so we can take advantage of multiple CPU cores
    pool_size = multiprocessing.cpu_count() * 2
    pool = multiprocessing.Pool(processes=pool_size, maxtasksperchild=4)
    worker_output = pool.map(func_to_parallelize, parallelable_data)
    pool.close() # no more tasks
    pool.join()  # wrap up current tasks
    # get the contents of our FakeLogger object
    while not logger_q.empty():
        print logger_q.get()
    print 'worker output contained: {}'.format(worker_output)

当然,这可能不会涵盖logging使用的全部内容,但我认为这个概念非常简单,可以快速、相对轻松地工作。而且修改应该很容易(例如lambda丢弃了一个可以传递到getLogger的可能的前缀)。

票数 3
EN

Stack Overflow用户

发布于 2013-12-02 15:59:34

所有Worker都共享同一个根记录器对象(在Worker.__init__中获得-- getLogger调用总是返回相同的记录器)。但是,每次创建Worker时,都会向该记录器添加一个处理程序(QueueHandler)。

因此,如果创建10个Worker,则根记录器上将有10个(相同的)处理程序,这意味着输出将重复10次。

相反,您应该使记录器成为一个模块属性,而不是一个实例属性,并在模块级别配置它一次--而不是在类级别。

(实际上,记录器应该在程序级别配置一次)

票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/20332359

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