我在想,能不能给我这样的短信:
ps:mandatory' child of Input command functions
Properties
ps:Source:
f47437
ps:Created:
2010-09-03T11:38:02.629Z
ps:ChangedBy:
F47437
ps:Changed:
2011-09-07T07:51:10.864Z以JSON格式。问题是,..that文件包含了成千上万的文本类型,它们就像树族一样。我的重点是将其转换为JSON,保存相同的树逻辑。我只想问我自己的知识。
发布于 2013-11-29 19:24:35
你是说像这样吗?
{
"ps:mandatory": "Properties",
"ps:Source:": "f47437",
"ps:Created:": "2010-09-03T11:38:02.629Z",
"ps:ChangedBy:": "F47437",
"ps:Changed:": "2011-09-07T07:51:10.864Z"
}重要的是要记住,JSON是无序的,所以在将其存储在JSON中时,很可能会丢失标记的顺序。如果订单很重要,请考虑另一种文件格式。
下面的代码将把上面的数据转换成JSON。汇编和工作:
import org.json.*;
public class CreateMyJSON
{
public static void main(String[] args)
{
String testData = "ps:mandatory\nProperties\n\nps:Source:\n f47437\n\nps:Created:\n 2010-09-03T11:38:02.629Z\n\nps:ChangedBy:\n F47437\n\nps:Changed:\n 2011-09-07T07:51:10.864Z\n\n";
CreateMyJSON cmj = new CreateMyJSON();
System.out.println(cmj.getJSONFromString(testData));
}
public String getJSONFromString(String theData)
{
JSONObject jso = new JSONObject();
//no error checking, but replacing double returns
//to make this simpler
String massagedData = theData.replaceAll("\n\n", "\n");
String[] splits = massagedData.split("\n");
for(int i = 0; i < splits.length; i++)
{
jso.put(splits[i].trim(), splits[++i].trim());
}
return jso.toString();
}
}https://stackoverflow.com/questions/20292186
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