在本例中,我有一个客户,它可以有许多PhoneNumbers。这些对象是:
The Customer
[Table(Name = "Customers")]
public class Customer : INotifyPropertyChanged
{
private String id;
private String givenName;
private String surname;
private EntitySet<PhoneNumber> phoneNumbers;
//INotifyPropertyChanged implementation was elided...
[Column(IsPrimaryKey=true, Storage="id", Name="Id", DbType="NVarChar(10) NOT NULL", CanBeNull=false)]
public String Id
{
get { return this.id; }
set
{
if (this.id != value)
{
this.id = value;
this.OnPropertyChanged("Id");
}
}
}
[Column(Storage="givenName", Name="GivenName", DbType="NVarChar(50) NOT NULL", CanBeNull=false)]
public String GivenName
{
get { return this.givenName; }
set
{
if (this.givenName != value)
{
this.givenName = value;
this.OnPropertyChanged("GivenName");
}
}
}
[Column(Storage="surname", Name="Surname", DbType="NVarChar(50) NOT NULL", CanBeNull=false)]
public String Surname
{
get { return this.surname; }
set
{
if (this.surname != value)
{
this.surname = value;
this.OnPropertyChanged("Surname");
}
}
}
[Association(Name="FK_PhoneBook_Customers", Storage = "phoneNumbers", ThisKey="Id", OtherKey = "CustomerId")]
public EntitySet<PhoneNumber> PhoneNumbers
{
get
{
return this.phoneNumbers;
}
set
{
if (this.phoneNumbers!= value)
{
this.phoneNumbers.Assign(value);
this.OnPropertyChanged("PhoneNumbers");
}
}
}
public Customer() { this.phoneNumbers = new EntitySet<PhoneNumber>(); }
}与PhoneNumber
[Table(Name = "PhoneBook")]
public class PhoneNumber: INotifyPropertyChanged
{
private int id;
private String customerId;
private String number;
private EntityRef<Customer> customer;
//INotifyPropertyChanged implementation was elided...
[Column(IsPrimaryKey=true, IsDbGenerated=true, Storage="id", Name="Id", DbType="int", CanBeNull=false)]
public int Id
{
get { return this.id; }
private set
{
if (this.id != value)
{
this.id = value;
this.OnPropertyChanged("Id");
}
}
}
[Column(Storage="customerId", Name="CustomerId", DbType="NVarChar(10) NOT NULL", CanBeNull=false)]
public String CustomerId
{
get { return this.customerId; }
set
{
if (this.customerId != value)
{
this.customerId = value;
this.OnPropertyChanged("CustomerId");
}
}
}
[Column(Storage="number", Name="Number", DbType="NVarChar(10) NOT NULL", CanBeNull=false)]
public String Number
{
get { return this.number; }
set
{
if (this.number != value)
{
this.number = value;
this.OnPropertyChanged("Number");
}
}
}
[Association(IsForeignKey=true, Name="FK_PhoneBook_Customers", ThisKey="CustomerId", OtherKey = "Id")]
public Customer Customer
{
get { return this.customer.Entity; }
set { this.customer.Entity = value; }
}
public PhoneNumber() { this.customer = new EntityRef<Customer>(); }
}我创建了一个DataContext并获得了一个客户(简化版本):
db = new DataContext(@"server=WIN-EL78137MUMS\SQLEXPRESS;database=SandBox;integrated security=SSPI");
// Get a typed table to run queries.
customers = db.GetTable<Customer>();
custQuery =
from cust in customers
orderby cust.Id
select cust;
Customer = custQuery.Skip(5).Take(1).First();在XAML中,我添加了DataGrid并将其绑定到Customer的PhoneNumbers属性。
<DataGrid ItemsSource="{Binding PhoneNumbers}" AutoGenerateColumns="False">
<DataGrid.Columns>
<DataGridTextColumn Header="Id" Binding="{Binding Id, Mode=OneWay, UpdateSourceTrigger=PropertyChanged}" />
<DataGridTextColumn Header="CustomerId" Binding="{Binding CustomerId, Mode=TwoWay, UpdateSourceTrigger=PropertyChanged}" />
<DataGridTextColumn Header="Number" Binding="{Binding Number, Mode=TwoWay, UpdateSourceTrigger=PropertyChanged}" />
</DataGrid.Columns>
</DataGrid>很抱歉做了长时间的介绍,这里是我的问题,还有一些问题--当我试图在网格中添加一个新的电话号码并调用db.SubmitChanges()时,我会收到以下错误消息:“试图删除客户和PhoneNumber之间的关系。但是,关系的一个外键(PhoneNumber.CustomerId)不能设置为null。”现在,我不希望用户在需要添加电话号码时不断地写入用户的id,因为正确的客户已经被选中,并且我正在尝试向他的号码集合中添加另一个号码。如何才能/应该这样做?
其他问题如下:
发布于 2013-11-29 19:07:55
好的,主要问题的答案很简单,在PhoneNumber中的关联属性中,我忘记了存储属性。正确的属性定义如下:
[Association(IsForeignKey=true, Name="FK_PhoneBook_Customers", Storage="customer", ThisKey="CustomerId", OtherKey = "Id")]
public Customer Customer
{
get { return this.customer.Entity; }
set { this.customer.Entity = value; }
}第二个问题的答案是“不”,如果没有它,我甚至根本不会面对主要的问题。但出于某种原因,Visual会创建此回引用。如果你们中有人知道为什么会有用,请分享你们的想法。
第三个问题的答案也是“不,它不应该被标记”。一旦一切都开始工作,没有任何关联属性附加到PhoneNumber.CustomerId属性,这就很明显了。
对于第四个问题,我也有一个部分的答案--“不,我不需要从两个结尾都给出相同的名字--它将继续用不同的名字命名。”但是,也许我应该给出相同的名字(同样,VS把它们命名完全相同),因为一些未知的和不需要的后果。再一次,请告诉我。
https://stackoverflow.com/questions/20275406
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