打印两个整数

Question

这可能是简单的，但我只是无法回避它，在目前的练习问题。我只是试着把几个整数打印在一起，以便输出

2004年是闰年。 2013年不是闰年

public class Ex1partA {
       public static void main(String[] args) {
       int year  = 2004;
       if(year%400==0){
           System.out.println("2004 is a leap year");
       }else if(year%100==0){
           System.out.println("2004 is not a leap year");
       }else if(year%4==0){
           System.out.println("2004 is a leap year");
       }else{
           System.out.println("2004 is not a leap year");
       }
   }
  
   {
        int year1  = 2013;
        if(year1%400==0){
        System.out.println("2013 is a leap year");
        }else if(year1%100==0){
        System.out.println(" 2013 is not a leap year");
        }else if(year1%4==0){
        System.out.println("2013 is a leap year");
        }else{
        System.out.println("2013 is not a leap year");
    
   }
 }
}

Answer 1

你想得太多了。只需使用这样一个简单的if-else。

int year = 2004;
if (year % 4 == 0) {
    System.out.println("2004 is a leap year");
} else {
    System.out.println("2004 is not a leap year");
}

int year1 = 2013;
if (year1 % 4 == 0) {
    System.out.println("2013 is a leap year");
} else {
    System.out.println("2013 is not a leap year");
}

您甚至可以将其移动到一个只需通过一年的方法中，它将为您显示结果。就像这样

public static void main(String[] args) {

    int year = 2004;
    checkLeapYear(year);

    int year1 = 2013;
    checkLeapYear(year1);
}

private static void checkLeapYear(int year) {
    if (year % 4 == 0) {
        System.out.println(year + " is a leap year");
    } else {
        System.out.println(year + " is not a leap year");
    }
}

Answer 2

您应该将非静态块代码放入main中，或者将其作为静态块来打印，2013年不是闰年。

公共类Ex1partA {

public static void main(String[] args) {
    int year = 2004;
    if (year % 400 == 0) {
        System.out.println("2004 is a leap year");
    } else if (year % 100 == 0) {
        System.out.println("2004 is not a leap year");
    } else if (year % 4 == 0) {
        System.out.println("2004 is a leap year");
    } else {
        System.out.println("2004 is not a leap year");
    }

    // Method#1

    {
        int year1 = 2013;
        if (year1 % 400 == 0) {
            System.out.println("2013 is a leap year");
        } else if (year1 % 100 == 0) {
            System.out.println(" 2013 is not a leap year");
        } else if (year1 % 4 == 0) {
            System.out.println("2013 is a leap year");
        } else {
            System.out.println("2013 is not a leap year");

        }
    }
}

// Method#2
static {
    int year1 = 2013;
    if (year1 % 400 == 0) {
        System.out.println("2013 is a leap year");
    } else if (year1 % 100 == 0) {
        System.out.println(" 2013 is not a leap year");
    } else if (year1 % 4 == 0) {
        System.out.println("2013 is a leap year");
    } else {
        System.out.println("2013 is not a leap year");

    }
}

 }

Answer 3

你的问题有点含糊，但你似乎有两个独立的街区。与您的主要方法一样，将其包含在一组大括号中，然后将下一个“语句”包含在单独的一组大括号中。编辑大括号，使主方法包含两个块。