我需要以下查询:
createList(string commaSeparatedElements) {
...
SqlCommand query = new SqlCommand("SELECT * FROM table WHERE id IN ("+commaSeparatedElements+")");
...
}我希望使用参数化查询来编写它,因此检查字符串中的每个元素,以防止Sql注入。
伪码:
createList(string commaSeparatedElements) {
...
SqlParameterList elements = new SqlParameterList("@elements", SqlDbType.Int);
SqlParameterList.Values = commaSeparatedElements.split(new Char[1] {','});
SqlCommand query = new SqlCommand("SELECT * FROM table WHERE id IN (@elements)");
query.Parameters.Add(elements);
...
}这样的东西是否存在于C#中,还是我必须自己写呢?
编辑:谢谢你所有的答案。由于我试图不使用代码,我不明白(过去的日子里有太多不好的经历),dapper和表值参数,尽管它们可能完美地满足我的需要,是不允许的。我刚做了个循环。
string[] elements = commaSeparatedElements.split(new Char[1] {','});
StringList idParamList = new StringList();
for(int i=0;i<elements.Count;i++) {
query.Parameters.AddWithValue("@element"+i,Convert.ToInt32(elements[i]));
idParamList.Add("@element" + i);
}
SqlCommand query = new SqlCommand("SELECT * FROM table WHERE id IN ("+String.Join(",",idParamList)+")");发布于 2013-11-22 11:10:03
我使用像这样的帮助方法
/// <summary>
/// Adds a sequence of parameters to an existing parameter collection
/// </summary>
/// <typeparam name="T">Type of parameter values</typeparam>
/// <param name="parameters">Existing parameter collection</param>
/// <param name="pattern">Name pattern of parameters. Must be a valid <see langword="int"/> format string</param>
/// <param name="parameterType">Database type of parameters</param>
/// <param name="length">Length of parameter. 0 for numeric parameters</param>
/// <param name="values">Sequence of values</param>
/// <returns>Comma separated string of parameter names</returns>
public static string AddParameters<T>(SqlParameterCollection parameters,
string pattern,
SqlDbType parameterType,
int length,
IEnumerable<T> values) {
if (parameters == null)
throw new ArgumentNullException("parameters");
if (pattern == null)
throw new ArgumentNullException("pattern");
if (values == null)
throw new ArgumentNullException("values");
if (!pattern.StartsWith("@", StringComparison.CurrentCultureIgnoreCase))
throw new ArgumentException("Pattern must start with '@'");
var parameterNames = new List<string>();
foreach (var item in values) {
var parameterName = parameterNames.Count.ToString(pattern, CultureInfo.InvariantCulture);
parameterNames.Add(parameterName);
parameters.Add(parameterName, parameterType, length).Value = item;
}
return string.Join(",", parameterNames.ToArray());
}它是这样使用的
string sql = "SELECT col1 " +
"FROM Table " +
"WHERE col2 IN ({@Values}) ";
var paramNames = SqlHelper.AddParameters(command.Parameters,
"@Value0",
SqlDbType.Int,
0,
listOfInts);
command.CommandText = sql.Replace("{@Values}", paramNames);
...(结果是类似于SELECT ... IN (@Value0, @Value1, @Value2)的查询)
发布于 2013-11-22 11:34:28
“衣冠楚楚”在这方面有一些伏都教:
var ids = new List<int> {1,2,3,4,5};
var rows = conn.Query<SomeType>("select * from table where id in @ids",
new { ids }).ToList();您将注意到in用法中缺少括号;"dapper“指出了这一点,并自动执行参数扩展。此外,它还为您处理所有的命令细节,包括将数据映射回SomeType实例。
在上面的例子中,它将扩展为相当于(大约):
int ids0 = 1, ids1 = 2, ids2 = 3, ids3 = 4, ids4 = 5;
var rows = conn.Query<SomeType>(
"select * from table where id in (@ids0,@ids1,@ids2,@ids3,@ids4)",
new { ids0, ids1, ids2, ids3, ids4 }).ToList();发布于 2013-11-22 10:57:28
Server有一个数据结构,它非常适合保存同一“类型”的多个值--这就是一个表。
值得庆幸的是,近年来,他们引入了表值参数,以便您可以在客户端代码中构造一个表,并以一种自然的方式将表传递给Server,例如:
// Assumes connection is an open SqlConnection.
using (connection)
{
// Create a DataTable with the modified rows.
DataTable addedCategories = CategoriesDataTable.GetChanges(
DataRowState.Added);
// Define the INSERT-SELECT statement.
string sqlInsert =
"INSERT INTO dbo.Categories (CategoryID, CategoryName)"
+ " SELECT nc.CategoryID, nc.CategoryName"
+ " FROM @tvpNewCategories AS nc;"
// Configure the command and parameter.
SqlCommand insertCommand = new SqlCommand(
sqlInsert, connection);
SqlParameter tvpParam = insertCommand.Parameters.AddWithValue(
"@tvpNewCategories", addedCategories);
tvpParam.SqlDbType = SqlDbType.Structured;
tvpParam.TypeName = "dbo.CategoryTableType";
// Execute the command.
insertCommand.ExecuteNonQuery();
}https://stackoverflow.com/questions/20143012
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