阵列在Tic脚趾的表现不像预期的那样？

Question

是我做的！...almost。

守则：

int main()
{
    //initialize
    char board[3][3] =
    {   '-','-','-',
        '-','-','-',
        '-','-','-'};
    bool gameOver = false;
    std::string playerTurn = "player 1";
    char chX, chY; //choice x and y
    int x = 1;

    //game loop
    do
    {
        std::cout << "\n\n\n\n\n\n\n\n\n\n";
        std::cout << "Input X, then Y.\np1 = X, p2 = O.";
        std::cout << "\n\nTurn: " << playerTurn;
        std::cout << "\n\n\n\n\n\n\n\n\n\n";
        std::cout << "+---+---+---+" << std::endl;
        std::cout << "| " << board[0][0] << " | " << board[0][1] << " | " << board[0][2] << " | " << std::endl;
        std::cout << "+---+---+---+" << std::endl;
        std::cout << "| " << board[1][0] << " | " << board[1][1] << " | " << board[1][2] << " | " << std::endl;
        std::cout << "+---+---+---+" << std::endl;
        std::cout << "| " << board[2][0] << " | " << board[2][1] << " | " << board[2][2] << " | " << std::endl;
        std::cout << "+---+---+---+" << std::endl;

        //get input and change board's value
        std::cin >> chX;
        std::cin >> chY;
        if (playerTurn == "player 1")
            board[chX][chY] = 'X';
        else if (playerTurn == "player 2")
            board[chX][chY] = 'O';

        //change turns
        if (playerTurn == "player 1")
            playerTurn = "player 2";
        else if (playerTurn == "player 2")
            playerTurn = "player 1";

    } while (gameOver == false);
    return 0;
}

我的问题是：

//get input and change board's value
std::cin >> chX;
std::cin >> chY;
if (playerTurn == "player 1")
    board[chX][chY] = 'X';
else if (playerTurn == "player 2")
    board[chX][chY] = 'O';

这一部分是为了将X和Y坐标改变为X/O，这取决于谁在转动它。然而，这根本不会改变董事会，也不会返回一个错误。另外：board[0][0] = 't';将成功地更改值，并在[0][0]点中打印t。

我遗漏了什么吗？也许问题就在代码的其他地方？(如果问题太简单，我会事先道歉--也许我喝了太多咖啡。)

Answer 1

这只是一个小错误--您将chX和chY定义为char，如果用户输入例如' 1 '，它是‘1’的ASCII代码，而不是整数值1。

只需将声明更改为

  int chX, chY;

而且它应该能工作。

Answer 2

正确地将chY和chX从chars更改为int，因为这是数组索引的方式。

然后在输入代码中使用这个

std::cout << "Enter X corrdinate: ";
std::cin >> chX;
std::cout << "\n";
std::cin.clear();
std::cout << "Enter Y corrdinate: ";
std::cin >> chY;
std::cin.clear();
if (playerTurn == "player 1")
    board[chX][chY] = 'X';
else if (playerTurn == "player 2")
    board[chX][chY] = 'O';

Id还创建了一个int类型的第二个数组板，这样您就可以检查玩家是否更容易获胜了。

Answer 3

char chX,chY; // valid values -127..128
std::cin >> chX; //gets ascii code of '0', '1' or whichever value you enter
std::cin >> chY;

问题是cin将返回您输入的字符的ascii代码；'0'=48；要获得整数值，只需减去'0'：

  std::cin >> chX; 
    std::cin >> chY;
    chX -= '0';
    chy -= '0';