Esqueleto‘`selectDistinct`’不工作

Question

selectDistinct似乎不适合我，这可能是一个简单的错误。查询：

 info <- runDB $ 
        E.selectDistinct $ 
        E.from $ \(tp `E.InnerJoin` rnd `E.InnerJoin` h) -> do
        E.on (rnd E.^. RoundId E.==. h E.^. HoleRound)
        E.on (tp E.^. TpartTournament E.==. rnd E.^. RoundTourn)
        E.where_ ((tp E.^. TpartTournament E.==. E.val tId ))
        E.orderBy [E.asc (tp E.^. TpartId)]
        return (tp, rnd, h)  

我确信这表示了sql查询，该查询工作如下：

SELECT DISTINCT tpart.id, round.name, hole.hole_num, hole.score
from tpart
inner join round on round.tourn = tpart.tournament
inner join hole on hole.round = round.id
where tpart.tournament = 1;

要查看结果，我有一个测试处理程序来打印结果表。注意，对于tpart 1，第1轮，有多个孔1和孔2。在postgresql中，SELECT DISTINICT删除了这些重复。

     TpartId, RoundName, holeNum, HoleScore

Key {unKey = PersistInt64 1}, round 1, 1, 6
Key {unKey = PersistInt64 1}, round 1, 2, 4
Key {unKey = PersistInt64 1}, round 1, 1, 6
Key {unKey = PersistInt64 1}, round 1, 2, 4
Key {unKey = PersistInt64 1}, round 1, 1, 6
Key {unKey = PersistInt64 1}, round 1, 2, 4
Key {unKey = PersistInt64 1}, round 2, 1, 3
Key {unKey = PersistInt64 1}, round 2, 2, 5
Key {unKey = PersistInt64 1}, round 2, 1, 3
Key {unKey = PersistInt64 1}, round 2, 2, 5
Key {unKey = PersistInt64 1}, round 2, 1, 3
Key {unKey = PersistInt64 1}, round 2, 2, 5
Key {unKey = PersistInt64 3}, round 1, 1, 6
Key {unKey = PersistInt64 3}, round 1, 2, 4
Key {unKey = PersistInt64 3}, round 1, 1, 6
Key {unKey = PersistInt64 3}, round 1, 2, 4
Key {unKey = PersistInt64 3}, round 1, 1, 6
Key {unKey = PersistInt64 3}, round 1, 2, 4
Key {unKey = PersistInt64 3}, round 2, 1, 3
Key {unKey = PersistInt64 3}, round 2, 2, 5
Key {unKey = PersistInt64 3}, round 2, 1, 3
Key {unKey = PersistInt64 3}, round 2, 2, 5
Key {unKey = PersistInt64 3}, round 2, 1, 3
Key {unKey = PersistInt64 3}, round 2, 2, 5

很抱歉我看不清。任何帮助都将不胜感激！

Answer 1

错误是，对于某个孔，孔的round和孔的part必须等于它们各自的部分。而且，在这种情况下，内部连接是多余的。