如何优化此查询?如果不使用ORDER子句运行它,它将在<100 in中执行。使用ORDER子句,它花费了许多秒时间,当多个系统试图同时执行此查询时,服务器就会崩溃。
UPDATE companies
SET
crawling = 1
WHERE
crawling = 0
AND url_host IS NOT NULL
ORDER BY
last_crawled ASC
LIMIT 1;如果我作为SELECT运行这个查询,它也是快速的(<100 as )。
SELECT id
FROM companies
WHERE
crawling = 0
AND url_host IS NOT NULL
ORDER BY
last_crawled ASC
LIMIT 1;下面是我的表模式:
CREATE TABLE `companies` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`url` varchar(255) DEFAULT NULL,
`url_scheme` varchar(10) DEFAULT NULL,
`url_host` varchar(255) DEFAULT NULL,
`name` varchar(255) DEFAULT NULL,
`crawl` tinyint(1) unsigned NOT NULL DEFAULT '1',
`crawling` tinyint(1) unsigned NOT NULL DEFAULT '0',
`last_crawled` datetime NOT NULL,
PRIMARY KEY (`id`),
KEY `name` (`name`),
KEY `url_host` (`url_host`),
KEY `crawl` (`crawl`),
KEY `crawling` (`crawling`),
KEY `last_crawled` (`last_crawled`),
KEY `url_scheme` (`url_scheme`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;更新一个
此查询给出以下错误:You can't specify target table 'companies' for update in FROM clause
UPDATE companies
SET crawling = 1
WHERE id = (
SELECT id
FROM companies
WHERE
crawling = 0
AND url_host IS NOT NULL
ORDER BY
last_crawled ASC
LIMIT 1
);此查询给出以下错误:This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'
UPDATE companies
SET crawling = 1
WHERE id in (
SELECT id
FROM companies
WHERE
crawling = 0
AND url_host IS NOT NULL
ORDER BY
last_crawled ASC
LIMIT 1
);发布于 2013-11-12 22:37:55
尽量不要对如此少量的更新使用ORDER和限制。
UPDATE companies t1
join
(
SELECT c.id,@RowNum:=@RowNum+1 AS RowID
FROM companies c, (SELECT @RowNum := 0)r
WHERE c.crawling = 0 AND c.url_host IS NOT NULL
ORDER BY c.last_crawled ASC
)t2
ON t2.RowID=1 AND t1.id=t2.id
SET t1.crawling = 1编辑:1
确保索引位于(last_crawled ASC,id ASC)上
UPDATE companies t1
join
(
Select ID,RowID
From
(
SELECT c.id,@RowNum:=@RowNum+1 AS RowID
FROM companies c, (SELECT @RowNum := 0)r
WHERE c.crawling = 0 AND c.url_host IS NOT NULL
ORDER BY c.last_crawled ASC
)t2
WHERE ROWID=1
)t3
ON t1.id=t3.id
SET t1.crawling = 1https://stackoverflow.com/questions/19940797
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