给定由幻影变量索引的GADT,我可以使用独立派生来创建一些简单的实例
data Client
data Temporary
data Permanent
data Token ty where
ClientToken :: Token Client
TemporaryToken :: ByteString -> ByteString -> Token Temporary
PermanentToken :: ByteString -> ByteString -> Token Permanent
deriving instance Eq (Token Client)
deriving instance Eq (Token Temporary)
deriving instance Eq (Token Permanent)在GHCi中似乎工作得很好
> ClientToken == ClientToken
True
> TemporaryToken "" "foo" == TemporaryToken "" "bar"
False但是,当我试图编译时,我会收到一个警告。
src/Network/HTTP/Conduit/OAuth/Types/Credentials.hs:72:1:
Couldn't match type `Client' with `Temporary'
Inaccessible code in
a pattern with constructor
TemporaryToken :: S8.ByteString
-> S8.ByteString -> Token Temporary,
in an equation for `=='
In the pattern: TemporaryToken a1 a2
In an equation for `==':
== (TemporaryToken a1 a2) (TemporaryToken b1 b2)
= (((a1 == b1)) && ((a2 == b2)))
When typechecking the code for `=='
in a standalone derived instance for `Eq (Token Client)':
To see the code I am typechecking, use -ddump-deriv
In the instance declaration for `Eq (Token Client)'这似乎是GADT派生代码(re:Haskell Inaccessible code bug?和https://ghc.haskell.org/trac/ghc/ticket/8128)中的一个but,但是由于它似乎有正确的行为,我想知道
-fno-warn-*标志关闭这些警告吗?如果可能的话发布于 2013-11-12 21:06:38
我在GHC7.6.3中测试了您的示例代码,至少在那里我得到了一个实际的编译错误,而不是GHCi和编译时的警告。自动实例派生似乎不够聪明,无法意识到它只需要将单个构造函数与给定的GADT匹配。
但是,下面的工作
data Client
data Temporary
data Permanent
data Token ty where
ClientToken :: Token Client
TemporaryToken :: ByteString -> ByteString -> Token Temporary
PermanentToken :: ByteString -> ByteString -> Token Permanent
deriving instance Eq (Token ty)但也许你真正的用例更复杂?
https://stackoverflow.com/questions/19939691
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