下面的代码将字符串@“10”变为2=102的幂,并将红色设置为数字2
问:我希望能产生这样的效果:

(请注意,我正在寻找一种通用效果,它代表一个较小的略高于一行的数字-就在字符串之后,而不一定是“到.的力量”,不过它应该看起来像上面的图像):
-(void)textAttribute
{
NSString *myString = @"ten to the power of two = 10[2]";
NSRange start = [myString rangeOfString:@"["];
NSRange end = [myString rangeOfString:@"]"];
if (start.location != NSNotFound && end.location != NSNotFound && end.location > start.location) {
//NSString *betweenBraces = [myString substringWithRange:NSMakeRange(start.location+1, end.location-(start.location+1))];
NSRange myRange = NSMakeRange(start.location+1, end.location-(start.location+1));
NSMutableAttributedString *s =
[[NSMutableAttributedString alloc] initWithString:myString];
UIColor *powerColor = [UIColor redColor];
[s addAttribute:NSForegroundColorAttributeName value:powerColor range:myRange];
triggerLabel.text = [NSString stringWithFormat:@"Trigger words:%@",powerColor];
triggerLabel.attributedText = s;
}
}发布于 2013-11-12 15:25:38
您不需要依赖特殊的字符,您只需要调整字符串的指数部分的基线,这样它就会超弱。
NSMutableAttributedString *attributedString = [[NSMutableAttributedString alloc] initWithString:@"ten to the power of 2 = 10"];
NSDictionary *exponentAttributes = @{
NSForegroundColorAttributeName : [UIColor redColor],
NSBaselineOffsetAttributeName : @(8)
};
NSAttributedString *exponentAttributedString = [[NSAttributedString alloc] initWithString:@"2" attributes:exponentAttributes];
[attributedString appendAttributedString:exponentAttributedString];
triggerLabel.attributedText = attributedString;您可以将其调整为使用所提供的标记来解析和构建字符串--这种方法是重要的部分。您可能也希望用NSFontAttributeName指定一个更小的字体。
https://stackoverflow.com/questions/19932838
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