嗨,我试图发送信息到我的本地mysql服务器,这是显示在续集pro。我在html中有一个表单,如下所示:
<a href="#openRegisterModal" id="main_header_register">register</a>
<div id="openRegisterModal" class="modalRegisterDialog">
<section>
<a href="#close" title="Close" class="close">X</a>
<h1>Register</h1>
<form name="registerform" class="registerform">
<label for="usernamefield">Username: </label>
<br>
<input type="text" id="usernameregisterfield"></input>
<br>
<label for="emailfield">Email: </label>
<br>
<input type="text" name="emailfield" id="emailregisterfield"></input>
<br>
<label for="passwordfield">Password: </label>
<br>
<input type="password" name="passwordfield" id="passwordregisterfield"></input>
<br>
<label for="passwordrepeatfield">Repeat Password: </label>
<br>
<input type="password" name="passwordrepeatfield" id="passwordrepeatregisterfield"></input>
<br>
<!--Check field-->
<br>
<input type="checkbox" name="agreementbox" id="agreementbox"></input>
<label for="agreementbox" id="termslink">I agree to the </label>
<a href="" id="termslink">terms</a>
<br>
<input type="button" id="registerbutton" value="Register" onclick="registerUser()">
</form>
</section>
</div>当我单击“注册”按钮时,应该调用这个javascript函数:
function initiate() {
}
function registerUser()
{
var username = document.getElementById("usernameregisterfield").value;
var email = document.getElementById("emailregisterfield").value;
var password = document.getElementById("passwordregisterfield").value;
console.log("Username: " + username);
console.log("Email: " + email);
console.log("Password: " + password);
if (window.XMLHttpRequest)
{
// Code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
}
else
{
// Code for IE6, IE5
xmlhttp = ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET",
"RegisterUser.php?username=" + username
+ "&email=" + email
+ "&password=" + password,
true);
xmlhttp.send();
}
initiate('load');然后调用这个php文件:
<?php
$username = strval($_GET['username']);
$email = strval($_GET['email']);
$password = strval($_GET['password']);
$connection = mysql_connect('localhost', 'root', '')
or die("Unable to connect to database");
$database = mysql_select_db("myDatabase")
or die("Could not select database");
$sql = "INSERT INTO registered_users VALUES ('$username', '$email', '$password');";
$execute = mysql_query($sql);
?>但当我试着做这件事时,什么都不会发生。我甚至没有收到错误信息。
谁来帮帮我!
发布于 2013-11-12 11:37:14
我认为您需要将$connection添加到查询中。
首先,将数据库添加到连接语句中。
$connection = mysql_connect('localhost', 'root', '', 'myDatabase')
or die("Unable to connect to database");然后,在构建查询之后,将下一行改为
$execute = mysql_query($connection, $sql);这都是假设您实际上正在访问PHP文件,而这正是问题所在。
发布于 2013-11-12 11:37:29
您没有添加数据库连接以选择DB。你应该写
$database = mysql_select_db("myDatabase", $connection)
or die("Could not select database");https://stackoverflow.com/questions/19927884
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