值在数据库中存储2次

Question

我必须在数据库中插入x&y触摸坐标值。但它在数据库中存储了2次。当我长时间按下时，我会得到触摸坐标，并为button_tag插入一些标记。但是我只按了一次，为什么值要存储2次？

表：

button_tag   xcoor    ycoor
2             123.5    320.9
23            123.5    320.9


- (void)tapTest:(UILongPressGestureRecognizer *)sender {
    NSLog(@"coordinate is %f %f", [sender locationInView:wbCont.scrollView].x, [sender locationInView:wbCont.scrollView].y);


     xcor = [sender locationInView:wbCont.scrollView].x;
     ycor = [sender locationInView:wbCont.scrollView].y;


    universal_button_tag = arc4random() % 99;

    NSLog(@"Universal Button tag: %d",universal_button_tag);

    NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory,NSUserDomainMask, YES);
    NSString *documentsDirectory = [paths objectAtIndex:0];


    NSString *path = [documentsDirectory stringByAppendingPathComponent:@"db.sqlite"];
    NSLog(@"filepath %@",path);


    if (sqlite3_open([path UTF8String], &database) == SQLITE_OK) {



        const char *sql = [[NSString stringWithFormat:@"SELECT button_tag,xcoor,ycoor FROM touch where  button_tag='%d' AND xcoor = '%f' AND ycoor = '%f'",universal_button_tag,xcor,ycor] cStringUsingEncoding:NSUTF8StringEncoding];


        NSLog(@"sql is %s",sql);

        BOOL favExist = false;

        sqlite3_stmt *statement, *addStmt;

        if (sqlite3_prepare_v2(database, sql, -1, &statement, NULL) == SQLITE_OK) {
            // We "step" through the results - once for each row.
            while (sqlite3_step(statement) == SQLITE_ROW) {



                favExist = true;
            }
        }


        if(!favExist){


            //Changes



            const char *sqlInsert = [[NSString stringWithFormat:@"insert into touch (button_tag,xcoor,ycoor) values ('%d','%f','%f')", universal_button_tag,xcor,ycor] cStringUsingEncoding:NSUTF8StringEncoding];

            //----

            NSLog(@"sql insert is %s",sqlInsert);


            // [catID release];

            if(sqlite3_prepare_v2(database, sqlInsert, -1, &addStmt, NULL) != SQLITE_OK)
                NSAssert1(0, @"Error while creating add statement. '%s'", sqlite3_errmsg(database));

            NSLog(@"error is %s",sqlite3_errmsg(database));

            if(SQLITE_DONE != sqlite3_step(addStmt))
                NSAssert1(0, @"Error while inserting data. '%s'", sqlite3_errmsg(database));


        }

    }

}

Answer 1

手势识别器的目标动作是针对手势识别器的不同状态调用的。您需要在您的方法中检查状态。

- (void)tapTest:(UILongPressGestureRecognizer *)sender {
    if (sender.state == UIGestureRecognizerStateEnded) {
        // handle completed gesture
    }
}

有关详细信息，请参阅UIGestureRecognizer的文档。