在java中对一个单词拆分字符串

Question

对于“狗”，我如何区分一个字符串--“懒散狗跑得快”，这样我就得到了Strings ="The Lazy"，“狗”，"is running“？在Java中

我使用的代码是字符串str=：“懒惰的狗像狗一样跑”；字符串dog=“狗”；String[] strArr= str.split(狗)；for(int i=0;i )

它会返回:懒惰者运行起来就像

Answer 1

我建议使用正则表达式 (和分组)。正则表达式可以用来匹配几乎任何你想要的东西！

例如：

import java.util.regex.*;

public class PatternExample {

    public static void main(String[] args) {
        String split = "The Lazy dog is running fast";
        Pattern pattern = Pattern.compile("(.*)(dog)(.*)");
        Matcher matcher = pattern.matcher(split);
        while (matcher.find()) {
            for (int i = 0; i <= matcher.groupCount(); i++){
                System.out.println(i + "->" + matcher.group(i));
            }
        }
    }
}

给予：

0->The Lazy dog is running fast
1->The Lazy 
2->dog
3-> is running fast

采取2:无正则表达式

public class PatternExample {

    public static void main(String[] args) {
        String split = "The Lazy dog is running fast";
        String word = "dog";
        String tmp = split;
        while (tmp.contains(word)){
            int x = tmp.indexOf(word);
            System.out.println(tmp.substring(0,x));
            System.out.println(word);
            tmp = tmp.substring(x+word.length());
        }
        System.out.println(tmp);
    }
}

Answer 2

我希望我正确地理解了你的问题，如果是这样的话，我将如何开始它，你仍然需要填补空白的边缘案例。您可以使用substring和indexOf来代替split，但是不使用它似乎太方便了。

package test;


public class Main {
    public static void main(String[] args) {
        String sentence = "The Lazy dog is running fast";
        String word = "dog";
        String[] splitByWord = splitByWord(word, sentence);
        for (String string : splitByWord) {
            System.out.println(string);
        }

    }

    public static String[] splitByWord(String word, String sentence) {
        String[] split = sentence.split(" " + word + " ");
        //TODO: handle edge cases where word is not found in sentence, or first word, or last
        return new String[]{split[0], word, split[1]};
    }
}