在下面的代码中,在按钮单击函数中,我想在picureBox中创建一个矩形,但是当我第一次执行它时,它没有绘制任何东西,但是第二次单击矩形会出现,为什么?
if语句在两段时间都是正确的。
private void btnChamber_Click(object sender, EventArgs e)
{
//pictureBox1.Visible = true;
if (cmbShowResult.SelectedIndex == 0 && ChamberType.SelectedIndex == 0)
{
chart1.Visible = false;
chart2.Visible = false;
chart3.Visible = false;
chart4.Visible = false;
chart5.Visible = false;
pictureBox1.Visible = true;
//pictureBox1.Enabled = true;
Graphics gg = pictureBox1.CreateGraphics();
//gg.ClipBounds.X = 0;
//gg.ClipBounds.Y = 0;
//AddChartStyle(gg);
chartArea1.X = 0;
chartArea1.Y = 0;
chartArea1.Height = 298;
chartArea1.Width = 450;
plotArea.X = 40;
plotArea.Y = 10;
plotArea.Height = 258;
plotArea.Width = 400;
xLimMin = -(float.Parse(txtWidth.Text)) / 2;
xLimMax = (float.Parse(txtWidth.Text)) / 2;
yLimMin = -(float.Parse(txtLeft.Text)) * 3f;
yLimMax = (float.Parse(txtLeft.Text)) * 3f;
Pen aPen = new Pen(chartBorderColor, 1f);
SolidBrush aBrush = new SolidBrush(chartBorderColor);
gg.FillRectangle(aBrush, chartArea1);
gg.DrawRectangle(aPen, chartArea1);
aPen = new Pen(plotBorderColor, 1f);
aBrush = new SolidBrush(plotBackColor);
gg.FillRectangle(aBrush, plotArea);
gg.DrawRectangle(aPen, plotArea);
//AddChartStyle(g);
//pictureBox1.Visible = true;
//gg = pictureBox1.CreateGraphics();
//gg.Flush();
//gg.Save();
//pictureBox1.Show();
//pictureBox1.Invalidate();
//chart6.Visible = true;
}
pictureBox1.Visible = true;
//gg.Flush();
}发布于 2013-10-29 17:21:42
因为你是在点击事件上这么做的。你应该在油漆事件上这么做。
https://stackoverflow.com/questions/19664718
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