python + urllib2代码错误

Question

我一直在尝试从一个网站中提取信息，但它似乎不起作用，而且每次运行它时我都会出错。

代码如下：

import urllib2, threading
def readpage():
    data = urllib2.urlopen('http://forums.zybez.net/runescape-2007-prices').read()
    for line in data:
        if 'forums.zybez.net/runescape-2007-prices/player/' in line:
            a = line.split('/runescape-2007-prices/player/'[1])
            print(a.split('">')[0])

t = threading.Timer(5.0, readpage)
t.start()

我知道这些错误：

Exception in thread Thread-1:
Traceback (most recent call last):
  File "C:\Python27\lib\threading.py", line 808, in __bootstrap_inner
    self.run()
  File "C:\Python27\lib\threading.py", line 1080, in run
    self.function(*self.args, **self.kwargs)
  File "C:\Users\Jordan\Desktop\username.py", line 3, in readpage
    data = urllib2.urlopen('http://forums.zybez.net/runescape-2007-prices').rea
()
  File "C:\Python27\lib\urllib2.py", line 127, in urlopen
    return _opener.open(url, data, timeout)
  File "C:\Python27\lib\urllib2.py", line 410, in open
    response = meth(req, response)
  File "C:\Python27\lib\urllib2.py", line 523, in http_response
    'http', request, response, code, msg, hdrs)
  File "C:\Python27\lib\urllib2.py", line 448, in error
    return self._call_chain(*args)
  File "C:\Python27\lib\urllib2.py", line 382, in _call_chain
    result = func(*args)
  File "C:\Python27\lib\urllib2.py", line 531, in http_error_default
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 403: Forbidden

非常感谢您的帮助，谢谢！

Answer 1

站点正在拒绝urllib2报告的默认用户代理。您可以使用install_opener对脚本中的所有请求进行更改。

opener = urllib2.build_opener()
opener.addheaders = [('User-agent', 'Mozilla/5.0 (X11; Linux i686; rv:5.0) Gecko/20100101 Firefox/5.0')]
urllib2.install_opener(opener)

您还需要通过站点将数据拆分，逐行读取数据

urllib2.urlopen('http://forums.zybez.net/runescape-2007-prices').read().splitlines()

和改变

line.split('/runescape-2007-prices/player/'[1])

至

line.split('/runescape-2007-prices/player/')[1]

工作：

import urllib2, threading

opener = urllib2.build_opener()
opener.addheaders = [('User-agent', 'Mozilla/5.0 (X11; Linux i686; rv:5.0) Gecko/20100101 Firefox/5.0')]
urllib2.install_opener(opener)

def readpage():
    data = urllib2.urlopen('http://forums.zybez.net/runescape-2007-prices').read().splitlines()
    for line in data:
        if 'forums.zybez.net/runescape-2007-prices/player/' in line:
            a = line.split('/runescape-2007-prices/player/')[1]
            print(a.split('">')[0])

t = threading.Timer(5.0, readpage)
t.start()

Answer 2

你试过在没有线的情况下打开那个网址吗？错误代码写着403:禁用，也许您需要对该网页进行身份验证。

Answer 3

这与Python无关--服务器拒绝您对该URL的请求。

我怀疑要么URL是不正确的，要么你已经达到某种速率限制，并被封锁。

编辑:如何使其工作

这个站点阻塞了Python的User-Agent。试试这个：

import urllib2, threading
def readpage():

    headers = { 'User-Agent' : 'Mozilla/5.0' }
    req = urllib2.Request('http://forums.zybez.net/runescape-2007-prices', None, headers)
    data = urllib2.urlopen(req).read()

    for line in data:
        if 'forums.zybez.net/runescape-2007-prices/player/' in line:
            a = line.split('/runescape-2007-prices/player/'[1])
            print(a.split('">')[0])