不能在一个类中加载简单html-dom类两次。

Question

当我试图将文件加载到dom对象中(在此之前清除它)时，dom变量是空的:(如何在类中使用simple-html-dom类两次？

<?php
require_once 'simple_html_dom.php';
class RO{
    public $dom;
    public $dom2;
    public function __construct(){
        $this->dom = new simple_html_dom();
        $this->dom2 = new simple_html_dom();
    }
    function GetDatumInUroPodatkovInTabKrajev($lang){
        $this->dom->load_file("http://www...diferentadresthenbelow...html");
        $tabelaTempInKrajev = $this->dom->find('table[@class="online"]');

        //some code...

        //some code...

        return $this->functon2("minkjaaa");
    }
    function functon2($ik){
        $this->dom2->load_file("http://www.arso.gov.si/vreme/napovedi%20in%20podatki/vreme_si.html");
        $tabelaVremRazm = $this->dom2->find('table[@class="online"]');    // this line trows an error, becaus dom2 is empty
        return"";
    }
}
?>

而trowen的错误是：

[Fatal error: Call to a member function find() on a non-object in C:\..\simple_html_dom.php on line ..]

Answer 1

除非指定了可选索引，否则Find("SELECTORS", index)查找将返回一个对象数组，然后返回Nth对象.这可能是你错过的..。下面是一个有用的例子：

// includes Simple HTML DOM Parser
include "simple_html_dom.php";

$url = "http://www.arso.gov.si/vreme/napovedi%20in%20podatki/vreme_si.html";

//Create a DOM object
$dom2 = new simple_html_dom();
// Load HTML from a string
$dom2->load_file($url);


// Find the link with the appropriate selectors
$table = $dom2->find('table.online', 0);


// Find succeeded
if ($table)
    echo $table->outertext;
else
    echo "Find function failed !";


// Clear DOM object (needed essentially when using many)
$dom2->clear(); 
unset($dom2);

在线演示