我试图得到两列之间的日期差异,然后最终得到按承包商字段分组的平均天数。我能够降低大部分SQL,但我似乎不知道如何获得多个if场景的日期差异。
基本上,如果原始日期列为空,而新日期列为空,则获取新日期和排序日期之间的日期差异。反之亦然。如果原始日期和新日期都为空,只需将日期差异设置为空。它应该如下所示,而不考虑分组的平均天数。

下面的SQL (还没有包含avg函数):
SELECT PT1.CONTRACTOR AS 'Contractor', PT1.date_order AS "date ordered", PT1.DATE_COMPLETED AS "original date", PT2.DATE_COMPLETED AS "new date",
IF(PT1.DATE_COMPLETED = NULL AND PT2.DATE_COMPLETED IS NOT NULL, DATEDIFF(PT2.DATE_COMPLETED, PT1.DATE_ORDER), IF(PT2.DATE_COMPLETED = NULL AND PT1.DATE_COMPLETED IS NOT NULL, DATEDIFF(PT1.DATE_COMPLETED, PT1.DATE_ORDER), NULL)) AS "DATE DIFF"
FROM PTABLE1 PT1
INNER JOIN PTABLE2 PT2
ON PT1.ID = PT2.ID
WHERE PT2.STATUS = 'To_do' OR PT2.STATUS = 'Completed'
AND PT2.COMPLETE = 'Yes'
-- GROUP BY PT1.CONTRACTOR发布于 2013-10-04 18:24:15
合并是您的朋友-它返回列表中的第一个非空值,如果它们都为空,则返回NULL。
所以你想要的可能是
datediff(coalesce(original_date, new_date), order_date)如果两者都为空,则datediff将返回null。
https://stackoverflow.com/questions/19188079
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